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之后的第三部分自动序列 (1) (Br0(n)=)) = )A164555号/A027642号和 (2) 溴(n)=) =A229979型/(c(n))=) =1,1,1,2,1,6,...=,... =1与交错A006955号或1,后跟A050932号.谢谢;谢谢到 _Jean-François Alcover公司)._).因此
溴(n))=) =0, 0, 1, 3/2, 1, 0, -1/2, 0, 2/3, 0, -3/2, 0, 5, 0, -691/30,...,, ...,
0,,0,,1,,3/2, 1,,0, -, -1/2,..., ...
0,,1,,1/2, -, -1/2, -1, -, -1/2,,1/2,..., ...
1, -, -1/2, -1, -, -1/2,,1/2, 1,,1/6,..., ...
--3/2, -, -1/2,,1/2, 1,,1/2, -, -5/6, -, -3/2,..., ...
1,,1,,1/2, -, -1/2, -, -4/3, -, -2/3, 2,..., ...
0, -, -1/2, -1, -, -5/6,,2/3,,8/3,,4/3,..., ...
--1/2, -, -1/2,,1/6,,3/2, 2, -, -4/3, -8,... ., ... .
第一贝努利多项式,即对于B(1))=-) = -1/2,,A196838号/A196839号,,使用0而不是空格:
1,,0, 0, 0, 0,,0,,0,,0, 0,..., ...
--1/2,,1, 0, 0, 0,,0,,0,,0, 0,..., ...
1/6, -, -1, 1, 0, 0,,0,,0,,0, 0,..., ...
0,,1/2, -3/2,,1, 0,,0,,0,,0, 0,..., ...
--1/30,,0, 1, -2, 1,,0,,0,,0, 0,..., ...
0, -, -1/6,,0,,5/3, -5/2, 1,,0,,0, 0,..., ...
1/42,,0, -, -1/2,,0,,5/2, -3,,1,,0, 0,..., ...
0,,1/6,,0, -, -7/6,,0,,0, -7/2, 1, 0,..., ...
--1/30,,0,,2/3,,0. -, -7/3, 0, 14/3, -4, 10,... ., ... .
第二列:A229979型/c(n)改为-1 属于 1,中的第一列A229979型.
第三列:Br2(n),带-3/2而不是3/2,第一个数组的第一列..
1, 1, 1, 1, 1, 1, 1, 1, 1, 1,..., ...
0, 1, 2, 3, 4, 5, 6, 7, 8, 9,... =, ... =A001477号,
0, 0, 1, 3, 6, 10, 15, 21, 28, 36,..., ...
0, 0, 0, 1, 4, 10, 20, 35, 56, 84,... ., ... .请参阅A052553号.
(Br0(n),),溴(n),),溴(n)),),Br3(n),...), ...导致A193815号)..)
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