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例子
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对于n=5,我们有:
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.两种安排总计
5个分区的分区k
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7 [5] [5] 5
6 [3+2] [3+2] 5
5 [4+1] [4 +1] 5
4 [2+1+1] [2+2 +1] 5
3 [3+1+1] [3 +1 +1] 5
2 [2+1+1+1] [2+1 +1 +1] 5
1 [1+1+1+1+1] [1+1+1 +1 +1] 5
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.两种安排
.区域编号的总和
5分区k的分区k
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7 [7] [7] 7
6 [6,7] [6,7] 13
5 [5,7] [5, 7] 12
4 [4,5,7] [4,5, 7] 16
3 [3,5,7] [3, 5, 7] 15
2 [2,3,5,7] [2,3, 5, 7] 17
1 [1,2,3,5,7] [1,2,3, 5, 7] 18
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所以三角形的第5行给出:18,17,15,16,12,13,7。
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三角形开始:
1;
3,2;
6,5,3;
11,10,8,9,5;
18,17,15,16,12,13,7;
29,28,26,27,23,24,18,28,20,21,11;
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