nmax1:=nmax;对于从0到nmax1的n,做cfn2(n,0):=1:cfn2 2*k1)/(2*kl))*(-1)^(k1+n)*cfn2(n-1,n-k1),k1=1..n)/(2*4^(n-1)*(2*n-1)!) end do:对于从1到nmax1的n do b(n):=(2*n)*(2*n-1)*denom(Delta(n-1))/(2^(2*n)*(2*n-1)!)end do:对于n从3到nmax1+1 do ZL(n):=cm(n-1)/cm(n-2)end do:seq(ZL(n),n=3..nmax1+1);