搜索: a261216-编号:a261216
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0, 0, 0, 5, 0, 3, 0, 0, 14, 16, 22, 20, 0, 19, 8, 20, 0, 7, 0, 13, 0, 7, 10, 16, 0, 0, 0, 5, 0, 3, 54, 54, 60, 65, 66, 69, 84, 90, 78, 95, 84, 81, 114, 108, 114, 107, 102, 111, 0, 0, 74, 76, 100, 98, 30, 30, 78, 83, 102, 105, 0, 19, 26, 45, 100, 119, 0, 13, 74, 87, 28, 41, 0, 97, 50, 98, 0, 49, 0, 97, 26, 117, 22, 47, 36, 108, 60, 113, 36, 63, 0, 25, 50, 33, 10, 59, 0, 73, 0, 49, 52
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通过共轭类似序列:
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交叉参考
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关键词
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非n
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作者
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状态
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经核准的
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1, 0, 5, 4, 3, 2, 7, 6, 11, 10, 9, 8, 19, 18, 23, 22, 21, 20, 13, 12, 17, 16, 15, 14, 25, 24, 29, 28, 27, 26, 31, 30, 35, 34, 33, 32, 43, 42, 47, 46, 45, 44, 37, 36, 41, 40, 39, 38, 49, 48, 53, 52, 51, 50, 55, 54, 59, 58, 57, 56, 67, 66, 71, 70, 69, 68, 61, 60, 65, 64, 63, 62, 97, 96, 101, 100, 99, 98, 103, 102, 107, 106, 105, 104, 115, 114, 119, 118, 117, 116, 109, 108, 113, 112, 111, 110, 73
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从列表中取第n个(n>=0)置换A060117号,将1更改为2,将2更改为1以获得另一个置换,并注意其在同一列表中的秩以获得a(n)。
非负整数的自逆置换。
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链接
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配方奶粉
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通过共轭相关排列:
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例子
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交叉参考
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关键词
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非n
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作者
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状态
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经核准的
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0, 1, 2, 3, 5, 4, 6, 7, 8, 9, 11, 10, 14, 15, 12, 13, 16, 17, 23, 22, 19, 18, 21, 20, 24, 25, 26, 27, 29, 28, 30, 31, 32, 33, 35, 34, 38, 39, 36, 37, 40, 41, 47, 46, 43, 42, 45, 44, 54, 55, 56, 57, 59, 58, 48, 49, 50, 51, 53, 52, 60, 61, 62, 63, 65, 64, 67, 66, 71, 70, 68, 69
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其他身份。对于所有n>=0:
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MAPLE公司
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A060126号(n) =PermRank3R(PermRevLexUnrank(n));
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交叉参考
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关键词
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非n,基础
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作者
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扩展
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状态
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经核准的
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0, 1, 2, 3, 5, 4, 6, 7, 8, 9, 11, 10, 14, 15, 12, 13, 16, 17, 21, 20, 23, 22, 19, 18, 24, 25, 26, 27, 29, 28, 30, 31, 32, 33, 35, 34, 38, 39, 36, 37, 40, 41, 45, 44, 47, 46, 43, 42, 54, 55, 56, 57, 59, 58, 48, 49, 50, 51, 53, 52, 60, 61, 62, 63, 65, 64, 67, 66, 70, 71, 69, 68
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作为其他排列的组合:
所有n>=0的其他恒等式:
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MAPLE公司
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A060119号(n) =PermRevLexRank(PermUnrank3R(n));
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交叉参考
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关键词
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非n,基础
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作者
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扩展
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状态
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经核准的
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0, 1, 1, 2, 0, 2, 3, 4, 3, 3, 4, 5, 0, 2, 4, 5, 2, 1, 5, 5, 5, 6, 3, 5, 4, 1, 4, 6, 7, 7, 4, 0, 0, 3, 7, 7, 8, 6, 12, 1, 3, 2, 8, 6, 8, 9, 10, 13, 13, 2, 1, 9, 10, 9, 9, 10, 11, 14, 12, 18, 0, 10, 11, 6, 8, 10, 11, 8, 15, 16, 19, 19, 11, 8, 7, 11, 11, 11, 12, 9, 16, 17, 20, 18, 0, 9, 11, 10, 7, 10, 12, 13, 18, 17, 14, 21, 22, 1, 1, 10, 6, 6, 9, 13, 13, 14, 19, 6, 15, 22, 23, 2, 0, 14, 7, 9, 8, 14, 12, 14
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方阵A(行>=0,列>=0)由向下反对偶读取为:A(0,0),A(0,1),A。。。
A(i,j)给出了表使用的排序A055089号)由不规则表中列为i-th和j-th排列的排列p和q合成得到的排列A055089号(注意,身份置换是第0个)。这里的约定是“左的置换作用”,因此,如果p1和p2是置换,那么p1和p2的乘积(p1*p2)被定义为(p1*p2)(i)=p1(p2(i)),对于i=1。。。
每一行和每一列都是A001477号,因为这是无限可枚举群的Cayley表(“乘法表”),即无限对称群(S_inf)的子群,它由只移动有限个元素的置换组成。
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链接
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配方奶粉
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通过与相关排列和阵列共轭:
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例子
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数组的左上角:
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, ...
1, 0, 4, 5, 2, 3, 7, 6, 10, 11, 8, 9, 18, ...
2, 3, 0, 1, 5, 4, 12, 13, 14, 15, 16, 17, 6, ...
3, 2, 5, 4, 0, 1, 13, 12, 16, 17, 14, 15, 19, ...
4, 5, 1, 0, 3, 2, 18, 19, 20, 21, 22, 23, 7, ...
5, 4, 3, 2, 1, 0, 19, 18, 22, 23, 20, 21, 13, ...
6, 7, 8, 9, 10, 11, 0, 1, 2, 3, 4, 5, 14, ...
7、6、10、11、8、9、1、0、4、5、2、3、20。。。
8, 9, 6, 7, 11, 10, 14, 15, 12, 13, 17, 16, 0, ...
9, 8, 11, 10, 6, 7, 15, 14, 17, 16, 12, 13, 21, ...
10, 11, 7, 6, 9, 8, 20, 21, 18, 19, 23, 22, 1, ...
11, 10, 9, 8, 7, 6, 21, 20, 23, 22, 18, 19, 15, ...
12, 13, 14, 15, 16, 17, 2, 3, 0, 1, 5, 4, 8, ...
...
对于A(1,2)(行=1,列=2,均从零开始),我们将在使用的顺序中秩为1的置换p作为置换A055089号,这是一个简单的换位(12),我们可以用固定项来扩展它(如{2,1,3,4,5,…}),作为置换q,我们采用秩为2的置换(在同一列表中),即{1,3,2}。我们从左边把它们组合起来,这样后一个q首先作用,因此c(i)=p(q(i)),结果是置换{2,3,1},它在A055089号因此A(1,2)=4。
对于A(2,1),我们以相反的顺序组合这两个置换,作为d(i)=q(p(i)),这给出了列为第三个置换的置换{3,1,2}A055089号,因此A(2,1)=3。
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交叉参考
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关键词
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作者
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状态
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经核准的
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0, 1, 1, 2, 0, 2, 3, 3, 4, 3, 4, 2, 0, 5, 4, 5, 5, 5, 1, 2, 5, 6, 4, 1, 4, 5, 3, 6, 7, 7, 3, 0, 0, 4, 7, 7, 8, 6, 8, 2, 3, 1, 12, 6, 8, 9, 9, 10, 9, 1, 2, 13, 13, 10, 9, 10, 8, 6, 11, 10, 0, 18, 12, 14, 11, 10, 11, 11, 11, 7, 8, 11, 19, 19, 16, 15, 8, 11, 12, 10, 7, 10, 11, 9, 0, 18, 20, 17, 16, 9, 12, 13, 13, 9, 6, 6, 10, 1, 1, 22, 21, 14, 17, 18, 13, 14, 12, 14, 8, 9, 7, 14, 0, 2, 23, 22, 15, 6, 19, 14
(列表;桌子;图表;参考;听;历史;文本;内部格式)
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偏移
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0,4
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评论
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链接
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配方奶粉
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通过与相关排列和阵列共轭:
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例子
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数组的左上角:
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, ...
1, 0, 3, 2, 5, 4, 7, 6, 9, 8, 11, 10, 13, ...
2, 4, 0, 5, 1, 3, 8, 10, 6, 11, 7, 9, 14, ...
3, 5, 1, 4, 0, 2, 9, 11, 7, 10, 6, 8, 15, ...
4, 2, 5, 0, 3, 1, 10, 8, 11, 6, 9, 7, 16, ...
5, 3, 4, 1, 2, 0, 11, 9, 10, 7, 8, 6, 17, ...
6, 7, 12, 13, 18, 19, 0, 1, 14, 15, 20, 21, 2, ...
7, 6, 13, 12, 19, 18, 1, 0, 15, 14, 21, 20, 3, ...
8、10、14、16、20、22、2、4、12、17、18、23、0、。。。
9, 11, 15, 17, 21, 23, 3, 5, 13, 16, 19, 22, 1, ...
10, 8, 16, 14, 22, 20, 4, 2, 17, 12, 23, 18, 5, ...
11, 9, 17, 15, 23, 21, 5, 3, 16, 13, 22, 19, 4, ...
12, 18, 6, 19, 7, 13, 14, 20, 0, 21, 1, 15, 8, ...
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交叉参考
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关键词
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作者
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状态
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经核准的
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0, 1, 1, 2, 0, 2, 3, 3, 5, 3, 4, 2, 0, 4, 4, 5, 5, 4, 1, 3, 5, 6, 4, 3, 5, 5, 2, 6, 7, 7, 1, 2, 1, 4, 7, 7, 8, 6, 8, 0, 0, 0, 14, 6, 8, 9, 9, 11, 9, 2, 1, 15, 15, 11, 9, 10, 8, 6, 10, 10, 3, 22, 14, 12, 10, 10, 11, 11, 10, 7, 9, 11, 23, 23, 16, 13, 9, 11, 12, 10, 9, 11, 11, 8, 0, 22, 21, 17, 17, 8, 12, 13, 13, 7, 8, 7, 10, 1, 1, 19, 20, 13, 16, 19, 13, 14, 12, 14, 6, 6, 6, 12, 0, 2, 18, 18, 12, 8, 18, 14
(列表;桌子;图表;参考;听;历史;文本;内部格式)
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方阵A(行>=0,列>=0)由向下反对偶读取为:A(0,0),A(0,1),A。。。
A(i,j)给出了等级(按表中使用的顺序)A060118号)由不规则表中列为i-th和j-th排列的排列p和q合成得到的排列A060118号(注意,身份置换是第0个)。这里的约定是“左的置换作用”,因此,如果p1和p2是置换,那么p1和p2的乘积(p1*p2)被定义为(p1*p2)(i)=p1(p2(i)),对于i=1。。。
每一行和每一列都是A001477号,因为这是无限可枚举群的Cayley表(“乘法表”),即无限对称群(S_inf)的子群,它由只移动有限个元素的置换组成。
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链接
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配方奶粉
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通过与相关排列和阵列共轭:
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例子
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数组的左上角:
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, ...
1, 0, 3, 2, 5, 4, 7, 6, 9, 8, 11, 10, 13, ...
2, 5, 0, 4, 3, 1, 8, 11, 6, 10, 9, 7, 14, ...
3、4、1、5、2、0、9、10、7、11、8、6、15。。。
4, 3, 5, 1, 0, 2, 10, 9, 11, 7, 6, 8, 16, ...
5, 2, 4, 0, 1, 3, 11, 8, 10, 6, 7, 9, 17, ...
6, 7, 14, 15, 22, 23, 0, 1, 12, 13, 18, 19, 8, ...
7, 6, 15, 14, 23, 22, 1, 0, 13, 12, 19, 18, 9, ...
8, 11, 12, 16, 21, 19, 2, 5, 14, 17, 20, 23, 6, ...
9, 10, 13, 17, 20, 18, 3, 4, 15, 16, 21, 22, 7, ...
10, 9, 17, 13, 18, 20, 4, 3, 16, 15, 22, 21, 11, ...
11, 8, 16, 12, 19, 21, 5, 2, 17, 14, 23, 20, 10, ...
12, 19, 8, 21, 16, 11, 14, 23, 2, 20, 17, 5, 0, ...
...
对于A(1,2)(行=1,列=2,均从零开始),我们将在使用的顺序中秩为1的置换p作为置换A060118号,这是一个简单的换位(12),我们可以用固定项来扩展它(如{2,1,3,4,5,…}),作为置换q,我们采用秩为2的置换(在同一列表中),即{1,3,2}。我们从左边把它们组合起来,这样后一个q首先作用,因此c(i)=p(q(i)),结果是置换{2,3,1},它在A060118号因此A(1,2)=3。
对于A(2,1),我们以相反的顺序组合这两个置换,作为d(i)=q(p(i)),这给出了列为第五个置换的置换{3,1,2}A060118号,因此A(2,1)=5。
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交叉参考
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关键词
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作者
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状态
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经核准的
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