以块表示法给出的a(3)=13停车函数为{1}、{2}、};{1,2},{},{3}; {1,2},{3},{}; {1},{2,3},{}; {1,2,3},{},{}; {1},{3},{2}; {1,3},{},{2}; {1,3},{2},{}; {2},{1},{3}; {2},{1,3},{}; {2},{3},{1}; {2,3},{},{1}; {2,3},{1},{}.
当n=3时,有5条Dyck路径:
w(NNNEEE)=[3],占总数的1;
w(NNENEE)=[2,1],对总和贡献2+1=3;
w(NNEENE)=[2,1],对总和贡献2+1=3;
w(东北)=[1,2],对总和贡献1+1=2;
w(NENENE)=[1,1,1],贡献(1+1)(1+1。
因此,a(3)=1+3+3+2+4=13。