显示1-1个结果(共1个)。
第页1
1, 1, -1, 12, -16, 1, 2160, -3312, 381, -1, 6048000, -10137600, 1603680, -10496, 1, 266716800000, -476703360000, 92708406000, -1022881200, 307505, -1, 186313420339200000, -349935855575040000, 78981336366912000, -1242627237734400, 750409713900, -9316560, 1
评论
行读取的三角形:对于0<=k<=n,T(n,k)是λ^k在det(H^(-1)-lambda I)中的系数,其中H是n x n Hilbert矩阵。
行总和为:1,0,-3,-772,-2496415,-118300727696,-85882975706265059,-97283586209103886316,-173520203650301344466515679407359,-48987775704995478381836257416,-2195456924460379495920541114453120558720536422853379
配方奶粉
t(n,m)=系数列表[Characteristic Polynomial[Inverse[HilbertMatrix[n]],x],x'
例子
{1},
{1, -1},
{12, -16, 1},
{2160, -3312, 381, -1},
{6048000, -10137600, 1603680, -10496, 1},
{266716800000, -476703360000, 92708406000, -1022881200, 307505, -1},
{186313420339200000, -349935855575040000, 78981336366912000, -1242627237734400, 750409713900, -9316560, 1}
MAPLE公司
f: =proc(n)使用线性代数;
局部λ,P,j;
P: =特征多项式(Hilbert矩阵(n),λ)/行列式(HilbertMatrix(n));
seq(系数(P,λ,n-j),j=0..n);
结束进程:
数学
<<线性代数`MatrixManipulation`;a=连接[{{1}},表[CoefficientList[CharacteristicPolynomial[Inverse[HilbertMatrix[n]],x],x]{n,1,10}]];压扁[a]
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