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示例
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数组的左上角:
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, ...
1, 0, 3, 2, 5, 4, 7, 6, 9, 8, 11, 10, 13, ...
2, 5, 0, 4, 3, 1, 8, 11, 6, 10, 9, 7, 14, ...
3, 4, 1, 5, 2, 0, 9, 10, 7, 11, 8, 6, 15, ...
4, 3, 5, 1, 0, 2, 10, 9, 11, 7, 6, 8, 16, ...
5, 2, 4, 0, 1, 3, 11, 8, 10, 6, 7, 9, 17, ...
6, 7, 14, 15, 22, 23, 0, 1, 12, 13, 18, 19, 8, ...
7, 6, 15, 14, 23, 22, 1, 0, 13, 12, 19, 18, 9, ...
8、11、12、16、21、19、2、5、14、17、20、23、6。。。
9, 10, 13, 17, 20, 18, 3, 4, 15, 16, 21, 22, 7, ...
10, 9, 17, 13, 18, 20, 4, 3, 16, 15, 22, 21, 11, ...
11, 8, 16, 12, 19, 21, 5, 2, 17, 14, 23, 20, 10, ...
12, 19, 8, 21, 16, 11, 14, 23, 2, 20, 17, 5, 0, ...
...
对于A(1,2)(行=1,列=2,均从零开始),我们将在使用的顺序中秩为1的置换p作为置换A060118号,这是一个简单的换位(12),我们可以用固定项来扩展它(如{2,1,3,4,5,…}),作为置换q,我们采用秩为2的置换(在同一列表中),即{1,3,2}。我们从左边把它们组合起来,这样后一个q首先作用,因此c(i)=p(q(i)),结果是置换{2,3,1},它在A060118号因此A(1,2)=3。
对于A(2,1),我们以相反的顺序组合这两个置换,作为d(i)=q(p(i)),这给出了列为第五个置换的置换{3,1,2}A060118号,因此A(2,1)=5。
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