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例子
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数组的左上角:
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, ...
1, 0, 5, 4, 3, 2, 7, 6, 11, 10, 9, 8, 19, ...
2, 3, 0, 1, 5, 4, 14, 15, 12, 13, 17, 16, 8, ...
3, 2, 4, 5, 1, 0, 15, 14, 16, 17, 13, 12, 21, ...
4, 5, 3, 2, 0, 1, 22, 23, 21, 20, 18, 19, 16, ...
5, 4, 1, 0, 2, 3, 23, 22, 19, 18, 20, 21, 11, ...
6, 7, 8, 9, 10, 11, 0, 1, 2, 3, 4, 5, 14, ...
7, 6, 11, 10, 9, 8, 1, 0, 5, 4, 3, 2, 23, ...
8、9、6、7、11、10、12、13、14、15、16、17、2。。。
9, 8, 10, 11, 7, 6, 13, 12, 17, 16, 15, 14, 20, ...
10, 11, 9, 8, 6, 7, 18, 19, 20, 21, 22, 23, 17, ...
11, 10, 7, 6, 8, 9, 19, 18, 23, 22, 21, 20, 5, ...
12, 13, 14, 15, 16, 17, 8, 9, 6, 7, 11, 10, 0, ...
...
对于A(1,2)(行=1,列=2,均从零开始),我们将在使用的顺序中秩为1的置换p作为置换A060117号,这是一个简单的换位(12),我们可以用固定项来扩展它(如{2,1,3,4,5,…}),作为置换q,我们采用秩为2的置换(在同一列表中),即{1,3,2}。我们从左边把它们组合起来,这样后一个q首先作用,因此c(i)=p(q(i)),结果是置换{2,3,1},它在A060117号因此A(1,2)=5。
对于A(2,1),我们以相反的顺序组合这两个置换,作为d(i)=q(p(i)),这给出了列为第三个置换的置换{3,1,2}A060117号,因此A(2,1)=3。
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