搜索： 编号：a234982
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A234982型
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| T（n，k）=（n+1）X（k+1）0..4个数组的数量，每个2X2子块的边差绝对值之和等于8 |
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+0
8
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182, 1664, 1664, 14420, 34862, 14420, 127982, 684282, 684282, 127982, 1127550, 13888792, 29606864, 13888792, 1127550, 9962574, 280501760, 1373159910, 1373159910, 280501760, 9962574, 87941706, 5681668040, 62993589692
(列表;桌子;图表;参考;听;历史;文本;内部格式)
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偏移
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1,1
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评论
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表格开始
......182.........1664...........14420.............127982...............1127550
.....1664........34862..........684282...........13888792.............280501760
....14420.......684282........29606864.........1373159910...........62993589692
...127982.....13888792......1373159910.......148913665958........16062528821746
..1127550....280501760.....62993589692.....16062528821746......4063185907422366
..9962574...5681668040...2917193420904...1752801119273172...1047618966093964184
.87941706.115047739004.134849510289180.191417616710931012.270097938511601692116
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链接
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配方奶粉
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k列的经验值：
k=1:a（n）=9*a（n-1）+13*a
k=2:[订单31]
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例子
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n=2k=4的一些解
..0..0..3..0..0....0..0..0..3..1....1..0..2..2..4....0..0..0..1..0
..0..4..4..4..1....0..4..1..0..2....0..3..4..0..4....0..4..2..4..1
..1..2..0..3..4....0..2..3..4..4....1..0..4..1..4....0..4..0..2..3
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关键字
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作者
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状态
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经核准的
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