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A250443型 |
| T(n,k)=(n+1)X(k+1)0..2数组的数量,每行和每列中每两个连续值的和不递减 |
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8
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81, 324, 324, 1296, 2160, 1296, 3600, 14400, 14400, 3600, 10000, 60000, 160000, 60000, 10000, 22500, 250000, 1000000, 1000000, 250000, 22500, 50625, 787500, 6250000, 8750000, 6250000, 787500, 50625, 99225, 2480625, 27562500, 76562500
(列表;桌子;图表;参考;听;历史;文本;内部格式)
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抵消
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1,1
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评论
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表格开始
.....81......324.......1296.........3600.........10000...........22500
....324.....2160......14400........60000........250000..........787500
...1296....14400.....160000......1000000.......6250000........27562500
...3600....60000....1000000......8750000......76562500.......450187500
..10000...250000....6250000.....76562500.....937890625......7353062500
..22500...787500...27562500....450187500....7353062500.....74118870000
..50625..2480625..121550625...2647102500...57648010000....747118209600
..99225..6482700..423536400..11859019200..332052537600...5379251109120
.194481.16941456.1475789056..53128406016.1912622616576..38730607985664
.345744.38723328.4337012736.195165573120.8782450790400.217365657062400
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链接
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配方奶粉
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对于k列来说,显然是一个8*k+8级的递归,一个4*k+4次多项式加上4*k+2次带周期的拟多项式:
k=1:[线性递归16阶;也是一个8次多项式加上一个带周期2的6次拟多项式]
k=2:[阶24;也是一个12次多项式加上一个带周期2的10次拟多项式]
k=3:[阶32;也是16次多项式加上带周期2的14次拟多项式]
k=4:[阶40;也是20次多项式加上带周期2的18次拟多项式]
k=5:[阶48;也是24次多项式加上22次拟多项式(周期2)]
k=6:[第56阶;也是28次多项式加上26次拟多项式,周期为2]
k=7:[阶64;也是32次多项式加上30次拟多项式,周期为2]
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例子
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n=3k=4的一些解
..0..0..0..0..0....0..0..0..2..0....0..0..0..2..0....0..0..0..0..0
..0..0..1..0..2....0..0..1..1..1....0..0..0..0..0....0..2..2..2..2
..0..2..0..2..2....0..2..0..2..1....0..1..0..2..1....1..0..2..1..2
..2..1..2..2..2....0..0..2..2..2....0..0..1..2..2....0..2..2..2..2
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交叉参考
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关键词
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作者
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状态
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经核准的
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