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A177717号 |
| 基于斐波那契多项式的对称三角形:p(x,n)=f(n,x)+x^(n-1)*f(n、1/x) |
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2, 1, 1, 2, 0, 2, 1, 2, 2, 1, 2, 0, 6, 0, 2, 1, 3, 4, 4, 3, 1, 2, 0, 11, 0, 11, 0, 2, 1, 4, 6, 10, 10, 6, 4, 1, 2, 0, 17, 0, 30, 0, 17, 0, 2, 1, 5, 8, 20, 21, 21, 20, 8, 5, 1
(列表;桌子;图表;参考;听;历史;文本;内部格式)
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抵消
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0,1
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评论
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行总和为:
{2, 2, 4, 6, 10, 16, 26, 42, 68, 110,...}
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参考文献
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函数形式使用自:http://functions.wolfram.com/HypergeometricFunctions/Fibonacci2General/26/01/02/0001/
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链接
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配方奶粉
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f(x,n)=(1/(2平方[4+z^2]))^2]);
p(x,n)=f(x,n)+x^(n-1)*f(1/x,n;
t(n,m)=系数(p(x,n))
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例子
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{2},
{1, 1},
{2, 0, 2},
{1, 2, 2, 1},
{2, 0, 6, 0, 2},
{1, 3, 4, 4, 3, 1},
{2, 0, 11, 0, 11, 0, 2},
{1, 4, 6, 10, 10, 6, 4, 1},
{2, 0, 17, 0, 30, 0, 17, 0, 2},
{1, 5, 8, 20, 21, 21, 20, 8, 5, 1}
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数学
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f[n,z_]:=(1/(2平方[4+z^2]))4+z^2])]]);
表[系数列表[FullSimplify[ExpandAll[f[n,x]+x^(n-1)*f[n、1/x]],x],{n,1,10}];
压扁[%]
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交叉参考
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关键词
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作者
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状态
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经核准的
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