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A156225号 |
| 行读取的三角形:e(n,k)=和[(-1)^j二项式[n+1,j](k+1-j)^n,{j,0,k+1}];t(n,m)=(e[n+1,m]*分区Q[n]+e[n+1,n-m]*(分区Q[n-m]+分区Q[m]))-2。 |
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1, 1, 1, 1, 10, 1, 3, 42, 42, 3, 3, 128, 262, 128, 3, 5, 340, 1810, 1810, 340, 5, 7, 958, 8335, 19326, 8335, 958, 7, 9, 2468, 38635, 140569, 140569, 38635, 2468, 9, 11, 6022, 160686, 970572, 1561898, 970572, 160686, 6022, 11, 15, 15193, 669758, 6372686
(列表;桌子;图表;参考;听;历史;文本;内部格式)
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抵消
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0,5
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评论
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行总和为:
{1, 2, 12, 90, 524, 4310, 37926, 363362, 3836480, 48184504, 643393254,...}.
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链接
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配方奶粉
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e(n,k)=和[(-1)^j二项式[n+1,j](k+1-j)^n,{j,0,k+1}];
t(n,m)=(e[n+1,m]*分区Q[n]+e[n+1,n-m]*(分区Q[n-m]+分区Q[m]))-2。
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例子
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{1},
{1, 1},
{1, 10, 1},
{3, 42, 42, 3},
{3, 128, 262, 128, 3},
{5, 340, 1810, 1810, 340, 5},
{7, 958, 8335, 19326, 8335, 958, 7},
{9, 2468, 38635, 140569, 140569, 38635, 2468, 9},
{11, 6022, 160686, 970572, 1561898, 970572, 160686, 6022, 11},
{15, 15193, 669758, 6372686, 17034600, 17034600, 6372686, 669758, 15193, 15},
{19, 38682, 2594827, 37459294, 155809822, 251587966, 155809822, 37459294, 2594827, 38682, 19}
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数学
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清除[e,k,t,n,m];
e[n_,k_]=和[(-1)^j二项式[n+1,j](k+1-j)^n,{j,0,k+1}];
t[n_,m_]=(e[n+1,m]*分区Q[n]+e[n+1,n-m]*(分区Q[n-m]+分区Q[m])-2;
表[表[t[n,m],{m,0,n}],{n,0,10}];
压扁[%]
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交叉参考
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关键词
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作者
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状态
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经核准的
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