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A253752型 |
| (4+1)X(n+1)0..2数组的数量,每2 X 2个子块ne-sw反对角线差在水平方向不减少,nw+se对角线和在垂直方向不减少。 |
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2
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7803, 75959, 382973, 1143174, 2351928, 4249381, 7348144, 11783014, 17227486, 24218260, 33845194, 46241656, 60632621, 78042368, 100341383, 127587830, 158431665, 194599303, 238993938, 291534619, 350130482, 417457176, 497739626
(列表;图表;参考;听;历史;文本;内部格式)
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抵消
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1,1
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评论
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链接
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配方奶粉
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经验公式:a(n)=3*a(n-1)-3*a(n-2)+a(n-3)+4*a(n4)-12*a(-n5)+12*a(n-6)-4*a(名词-7)-6*a n-19)对于n>27。
n mod 4=0的经验公式:a(n)=(4873/23040)*n^6+(241919/15360)*n*5+(3034139/4608)*n_4+(4726559/384)*n_3+(7406437/90)*n_2-(15218987/30)*n+1005182,对于n>8。
n mod 4=1的经验:a(n)=(4873/2340)*n^6+(241919/15360)*n*5+(3034139/4608)*n_4+(18843205/1536)*n_3+(1878126757/23040)*n_2-(2674526163/5120)*n+(522413747/512),对于n>8。
n mod 4=2的经验:a(n)=(4873/23040)*n^6+(241919/15360)*n*5+(3034139/4608)*n_4+(146755/12)*n_3+(14433929/180)*n_2-(525506959/960)*n+(34331513/32),对于n>8。
n mod 4=3的经验:a(n)=(4873/23040)*n^6+(241919/15360)*n*5+(3034139/4608)*n_4+(18844129/1536)*n_3+(1862199637/23040,)*n_2-(2736248123/5120)*n+(544432283/512),对于n>8。
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例子
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n=2的一些解
..2..0..0....0..0..2....1..0..1....0..1..2....0..0..2....1..0..0....1..0..0
..1..0..0....0..0..0....2..0..2....2..1..0....0..0..1....1..0..0....1..0..2
..1..1..1....2..0..0....1..0..2....2..1..2....0..0..1....2..0..1....2..1..2
..2..1..1....2..0..1....2..1..2....1..1..2....2..2..1....2..1..1....2..1..2
..2..0..1....2..2..1....0..1..2....1..2..2....2..0..0....2..2..0....1..1..2
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交叉参考
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关键词
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非n
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作者
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状态
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经核准的
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