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7, 11, 15, 18, 22, 25, 28, 31, 34, 37, 39, 42, 45, 48, 51, 53, 56, 59, 61, 64, 67, 69, 72, 75, 77, 80, 82, 85, 88, 90, 93, 95, 98, 101, 103, 106, 108, 111, 113, 116, 118, 121, 124, 126, 129, 131, 134, 136, 139, 141, 144, 146, 149, 151, 154, 156, 159, 161
(列表;图表;参考;听;历史;文本;内部格式)
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抵消
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1,1
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链接
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例子
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(A248630型(k+1)=A248360型(k) )=(2,2,2,2,1,2,2,1,1,2,2,2,2,2,2,2,1,…),因此A248630型= (7, 11, 15, 18, ...).
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数学
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z=300;p[k_]:=p[k]=和[(h^2/2^h),{h,1,k}]
d=N[表[6-p[k],{k,1,z/5}],12]
f[n_]:=f[n]=选择[Range[z],6-p[#]<1/3 ^n&,1]
d=差异[u]
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交叉参考
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关键词
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非n,容易的
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作者
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状态
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经核准的
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