表格开始:
1, 0, 0, 0, 0, 0, 0, 0, 0, 0 ...
3, 0, 0, 0, 0, 0, 0, 0, 0, 0 ...
8, 4, 0, 0, 0, 0, 0, 0, 0, 0 ...
20, 15, 0, 0, 0, 0, 0, 0, 0, 0 ...
47, 37, 16, 0, 0, 0, 0, 0, 0, 0 ...
107, 87, 60, 0, 0, 0, 0, 0, 0, 0 ...
238, 200, 169, 64, 0, 0, 0, 0, 0, 0 ...
520, 448, 387, 240, 0, 0, 0, 0, 0, 0 ...
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对于T(5,2),我们计算包含{1,3,5}的{1,…,5}子集,这里只有d=2AP可能。有4个子集包含{1,3,5},因此T(5,2)=4。