subset

A mathematical concept
Collection
zero Useful+1
zero
subset It is a mathematical concept: if a set A Of Any element All are collections B Element of, then set A Is called a set B Of subset
Symbolic language: Ruo ∀ a A. Average yes a B , then A B。
Chinese name
subset
Foreign name
subset
application area
Mathematical Science
Application category
aggregate
Represent
∀ a ∈ A, all a ∈ B, then A ⊆ B

catalog

definition

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If set A Any element of is a collection B Element of (any a A be a B ), then set A Is called a set B Of subset , marked as A ⊆ B or B A , read as "set A contain Gather on B ”Or set B Include Collection A ”。
Namely: ∀ a A yes a B , then A B [1]
If set A yes B A subset of, and A B , i.e B At least one element in does not belong to A , then A namely B Of Proper subset , can be recorded as: A⊂ B [4 ]
Symbolic language: Ruo ∀ a A. Average yes a B , and
X ∈ B makes x ∉ A, then A B。
Figure 1
As shown in Figure 1, set A is the proper subset of set B. [2]

nature

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1、 According to the definition of subset, we know that A A in other words, Any set is a subset of itself
2、 For the empty set ∅, we specify ∅ ⊆ A I.e empty set Is any aggregate Subset of
Note: If A=∅, ∅ ⊆ A is still valid.
Proof: Given any set A, it is necessary to prove that ∅ is a subset of A. This requires that all ∅ elements are A elements; However, ∅ has no element. For experienced mathematicians, it is obvious to infer that "∅ has no elements, so all elements of ∅ are elements of A"; but for beginners, there is some trouble. Because ∅ has no elements, how to make "these elements" become elements of other sets? Another way of thinking will help.
In order to prove that ∅ is not a subset of A, you must find an element that belongs to ∅ but does not belong to A. Because ∅ has no element, this is impossible. Therefore ∅ must be a subset of A.
3、 If A, B and C are sets, then:
Reflexivity: A=A
Anti symmetry: if and only if
And
When,
Transitivity : If
And
, then
This proposition shows that inclusion is a kind of Partial order relation
IV
This proposition shows that for any set S, S Power set The order by inclusion is a bounded lattice. If it is combined with the above proposition, it is a Boolean algebra
5、 : For any two aggregate A and B, all of the following expressions are equivalent:
  • A ⊆ B
  • A ∩ B =A
  • A ∪ B = B
  • A − B=A (when A ∨ B=∅); A − B=C 𝖠 (A 𝖠 B) (when A 𝖠 B ≠∅)
  • B′ ⊆ A′
This proposition explains: expressing "A ⊆ B" and other uses Union , intersection and Complement The expression of is equivalent, that is, the inclusion relation is redundant in the axiom system.
6、 Assumptions Non empty set A With n Elements, there are:
  • The number of subsets of A is 2 n
  • The number of proper subsets of A is 2 n -1。
  • The number of non empty subsets of A is 2 n -1
  • The number of non empty proper subsets of A is 2 n -2。 [3]