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reactant

A substance that can participate in a chemical reaction
open 2 entries with the same name
stay chemical reaction The substance that can participate in the reaction is called reactant, which refers to the substance that can be consumed in a chemical reaction. chemical reaction The solvents and catalysts involved are not counted as reactants.
Chinese name
reactant
Foreign name
Reactant
Interpretation
stay chemical reaction Medium, substance that can participate in the reaction
Field
Chemistry

Basic information

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stay chemical reaction The substance that can participate in the reaction is called reactant. (In biology, it is called substrate or acceptor) chemical reaction A substance that can be consumed in. Although solvents and catalysts are generally involved in chemical reactions, they are not usually counted as reactants.
Reagents emphasize a specific use of this chemical.
Relevant information
Write this Ionic equation First of all, it is necessary to find out the ratio of reactants. If the ratio is not told, it is necessary to find out the order of dropping. Generally speaking, the reactant in the dropper is not enough when starting to drip, while the conical flask (or beaker, etc Reaction vessel )Excessive reactants in. about Neutralization reaction For example, if the alkali is excessive, the neutralization product is Orthosalt , if acid or Acid gas In case of excessive reaction with alkali, it may generate Acid salt (Yes Polybasic acid For). stay Redox reaction Medium, if Oxidant In case of excess, all elements that can be oxidized will be oxidized; If the oxidant is insufficient Reducibility Strong elements are oxidized first, like Cl two And FeBr two The solution reacts like that.

Related reactions

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A reaction in which the product can continue to react with the excess reactant
Example 1. CO two Inject excessive NaOH solution: CO two +2OH - =CO three 2- +H two O
Excess CO2 into NaOH solution: CO two +OH - =HCO three -
Example 2: A small amount of NaOH solution is dropped into AlCl3 solution to react with Al 3+ +3OH =Al(OH) three
Small amount of AlCl three Solution dropping into NaOH solution reaction: Al 3+ +4OH ==AlO two +2H two O
Example 3. FeCl three Solution and Na two S solution reaction
Fe 3+ And S 2- Can occur Redox reaction Generate Fe 2+ , while Fe 2+ And S 2- It can react to generate FeS precipitation, which is soluble in acid solution, so it writes the ion reaction equation High attention should be paid to.
(1) When n (FeCl three )∶n(Na two S) ≥ 2:1, namely FeCl three Sufficient, when the solution is acidic.
2Fe 3+ +S 2- =2Fe 2+ +S↓
(2) When n (FeCl three )∶n(Na two S) ≤ 2:3, i.e. Na two S sufficient, when the solution is alkaline.
2Fe 3+ +3S 2- =2FeS↓+S↓
(3) When n (FeCl three )When: n (Na2S)=1 ∶ 1, Na2S and FeCl3 react completely.
2Fe3++2S 2- =FeS↓+S↓+Fe 2+
Summary: write correctly Ionic reaction equation The key lies in:
① Determine whether a certain reactant is insufficient, excessive or appropriate according to the dosage ratio of reactants.
② Determine whether the product reacts with excessive reactants.
Special reaction
Some Ionic reaction In addition to the relationship between the amount of reactants, other special factors should be considered to correctly write the ionic reaction equation
Example 1. Newly prepared chlorine water and FeBr two Solution reaction
In addition to the relationship between the amount of reactants, the reaction should also consider the relationship between Fe2+and Br - Reducibility Strength. Because Fe2+ Reducibility Better than Br -, so Cl two Pre oxidized Fe 2+ , post oxidation Br
(1) When n (FeBr two )∶n(Cl two )≥ 2:1, i.e. FeBr two A small amount of chlorine water is dropped into the solution reaction.
2Fe 2+ +Cl two =2Fe 3+ +2Cl
(2) When n (FeBr two )∶n(Cl two )≤ 2:3, i.e. FeBr two Drop sufficient chlorine water into the solution reaction.
2Fe 2+ +4Br +3Cl two =2Fe 3+ +2Br two +6Cl
(3) When 2 ∶ 3<n (FeBr two )∶n(Cl two )<2:1, for example, to 20mL0.1mol/L FeBr two Fill the solution with 44.8mL chlorine under standard conditions. First, calculate n (FeBr two )∶n(Cl two )=1 ∶ 1, and then write the ion reaction equation
2Fe 2+ +2Br +2Cl two =2Fe 3+ +Br two +4Cl
Note: Newly made Chlorine water And FeI two Solution reaction; Because I - Reducibility Ratio Fe 2+ Strong, so Cl two Pre oxidation I , post oxidized Fe 2+
Example 2. Mg (HCO three ) two Solution reacts with NaOH solution
In addition to the relationship between the amount of reactants, ① Mg (OH) two Of solubility Ratio MgCO three The solubility of is smaller, and the precipitate generated after reaction is Mg (OH) two Not MgCO three 。② OH - reacts with Mg2+first and then with HCO3 -.
(1) When n [Mg (HCO three ) two ]When: n (NaOH) ≤ 1:4, NaOH is sufficient.
Mg 2+ +2HCO three +4OH =Mg(OH) two ↓+2CO three 2- +2H two O
(2) When n [Mg (HCO three ) two ]When: n (NaOH) ≥ 1 ∶ 2, that is, a small amount of NaOH.
Mg 2+ +2OH =Mg(OH) two
(3) When 1:43) 2]: n (NaOH) ≤ 1:3, such as n [Mg (HCO three ) two ]∶n(NaOH) =1∶3
Mg 2+ +HCO 3- +3OH =Mg(OH) two ↓+CO three 2- +H two O
(4) When 1 ∶ 3<n [Mg (HCO three ) two ]When: n (NaOH)<1:2, such as n [Mg (HCO three ) two ]∶n(NaOH) =5∶12
5Mg 2+ +2HCO three +12OH =5Mg(OH) two ↓+2CO three 2- +2H two O
To sum up: different ionic reactions with different reactant dosage ratio equation The writing of should be based on the nature of ions, the amount of reactants and the specific analysis of the reaction environment, and flexible use can be written correctly.
Speculative product
First, remember some colored substances or substances with special properties, which are often the starting point for solving problems, such as red: Cu; Cu2O; Red phosphorus (dark red), Fe two O three (brownish red), Fe (OH) three (reddish brown), [Fe (SCN)] 2+(blood red), liquid Br two (dark reddish brown), Br two Water (orange), Br two (CCl four )Reddish brown, Br two Steam (reddish brown), NO two (reddish brown) yellow: Agl (yellow), Ag three PO four (yellow), S (light yellow), Na two O two (light yellow), AgBr (light yellow), FeCl three (brown yellow), I two Water (brown yellow), Fe 3+ (brown yellow), Cl two (yellow green) Blue: CuSO four ·5H two O、Cu(OH) two 、Cu 2+ Solution green: FeSO four ·7H two O、Fe
Second, remember some industrial reactions, such as Chlor alkali industry , sulfuric acid industry, etc
Third, remember some special reaction conditions, such as electrolysis, and think that it may be electrolysis of saturated sodium chloride or electrolysis of molten aluminum oxide; high temperature According to whether the reaction is Simple substance Participate or generate, and determine whether metal participates or not Thermite reaction , iron and Water vapor Reactions, etc., as well as some continuous oxidation problems such as H two O-SO two -SO three -H two SO four ,NH three -NO-NO two -HNO three

Effect of activity

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The reactivity of the same substance in different structural states varies greatly.
The more complete the structure of reactants is, the fewer character defects are, which is not conducive to diffusion, and the solid phase reaction speed is slow. Strong bonding force between particles, firm structure, high character and low reactivity.
The process of polycrystalline transformation is often accompanied by lattice rearrangement, which makes the lattice loose and activated. E.g. SiO two Polycrystalline transformation can make the lattice loose and activated, and easy to break.
Thermal decomposition and dehydration: because gas and steam are discharged from the crystal, the lattice has a large specific surface area and lattice defects, or becomes amorphous after decomposition and dehydration, which increases the reaction activity and accelerates the solid phase reaction. For example, light burned raw materials have much higher reaction activity than dead burned raw materials, CaCO three Decompose under light burning to obtain loose and porous CaO, which is beneficial to the combination of CaO and SiO two Reaction, generating C two S。 Kaolinite Al two O three ·2SiO two ·2H two O heating and dehydration to obtain metakaolinite Al two O three ·2SiO two , continue heating to obtain Al with certain activity two O three And SiO two [1]