Calculation of pump effective power

2012-10-21 20:17 | Publisher: helloshigy | see: fifty thousand and seventy-two | Comments: two

abstract : The effective power of the pump is calculated. The effective power represents the effective energy head of the liquid pumped out from the pump in a unit time.

Note: Please enter three of the four items and set the unit, then click the Calculate button to calculate the other item. The input must be a numeric value or a legal formula
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Density (ρ):

Head (H):

Flow (Q):

Effective power (N_e ):

Calculation results

Basis description

The effective power refers to the effective energy head obtained from the pump for the liquid pumped out in unit time.

According to the formula

Calculate

Wherein, ρ - liquid density, kg/m^three ； H -- The head of the pump is the energy head obtained after the liquid of unit weight passes through the pump, in m; Q -- Volume flow, m^three /s

Please enter the function in the following table format. Functions or expressions can be nested in the function
For example: 3.14 * pow (5 * lg (4 * 8), 4+8 * sin (30))
The unit of trigonometric function is degree

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Latest comments

quote zxt2018 2019-2-12 14:47: Good data Good data

quote Free flight 2012-11-7 09:15: Is this different from the hydraulic power above? Why didn't you calculate the shaft power?

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Calculation of pump effective power

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