来自在线整数百科全书的问候语!http://oeis.org/ Search: id:a328238 Showing 1-1 of 1 %I A328238 %S A328238 4,5,3,7,12,9,16,10,20,13,7,15,28,42,6,19,16,21,18,42,44,25,48,14,52, %T A328238 3,26,31,60,33,8,66,68,43,9,39,56,51,80,43,84,45,19,37,92,49,13,18,24, %U A328238 236,46,55,16,67,112,138,88,61,116,63,124,124,12,130,132,69,82,138,140,73,28,75,119,84,108,142,156,81,44,7,164 %N A328238 Quotient A003415(n*m)/A003415(n) for the least m > 1 for which such a quotient is an integer. 这里A000 315(x)是X.%%H A328、Antti Karttunen的算术导数,n,a(n)n=2…16385的表%H A328、Antti Karttunen数据补充:n,a(n)计算n=2…65537。%F A328 38A(n)=A00 31515(N*A328 23 6(n))/A00 34 15(n)。εe A328 88算术导数为6′=6′=A00 34 15(6)=5。取其连续倍数的算术导数,我们得到12′=16, 18′=21, 24′=44, 30′=31,而不是直到用A00 34 15(6×6)=36′=60时,我们得到5的倍数。因此A(6)=60/5=12 .0%O A328 328(PARI)%A328 23 8 A00 34 15(n)=In(n=1, 0,i(f=因子(n));n*和(i=1,αff,f[i,2 ] /f[i,1 ]);%%o a328 23 8a328 23 8(n)={i(d=a00)(n),(m=2,O,IF)(!T=A00 31515(n*m)(%/d),返回(t/d);};%Y3A3158,A000 34 15,A328 23 7。((