搜索: 编号:a237632
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A237632型
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| (n+1)X(3+1)0..2数组的数量,每个2X2子块的上中位数与其水平和垂直相邻块相差正好一。 |
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+0 1
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702, 1220, 1310, 1488, 2086, 2900, 4132, 5720, 8248, 11504, 16546, 22928, 33024, 46016, 66184, 91712, 132096, 184064, 264736, 366848, 528384, 736256, 1058944, 1467392, 2113536, 2945024, 4235776, 5869568, 8454144, 11780096, 16943104
(列表;图表;参考;听;历史;文本;内部格式)
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抵消
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1,1
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链接
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配方奶粉
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经验:对于n>13,a(n)=4*a(n-4)。
经验公式:2*x*(351+610*x+655*x^2+744*x^3-361*x^4-990*x^5-554*x^6-116*x^7-48*x^8-48*x ^9+9*x^10+24*x*^11+16*x ^12)/((1-2*x^2)*(1+2*x^ 2))-科林·巴克2018年10月24日
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例子
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n=5的一些解决方案:
..1..2..0..1....0..0..2..1....2..2..0..0....2..0..1..0....2..1..0..0
..0..0..0..2....1..0..1..2....1..1..0..1....1..2..0..0....1..2..0..1
..0..1..2..1....2..0..0..0....0..0..0..2....0..0..2..1....0..1..2..1
..1..2..0...0...1..2..1...0...0...1...2...1...0...1...2...0...0...0...0...2
..2..1..0..2....0..0..2..0....0..2..0..0....2..0..0..0....1..2..0..1
..1..0..0..1....0..1..1..2....2..1..0..2....2..1..2..0....2..1..0..0
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交叉参考
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关键词
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非n
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作者
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状态
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经核准的
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