#来自在线整数序列百科全书的问候!1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,59,1,53,53,1,53,53,1,53,53,1,53,53,1,53,1,53,53,1,53,53,1,53,53,53,53,53,53,53,53,53,53 110,79,79,79,79,79,79,79,86,99,86,86,86,79,79,79,79,79,86,86,86,86,86,86,86,86,86,86,86,86,79,79,79,79,79,79,86,86,99,86,86,76,79,79,79,79,79,86,86,76,86,79,79,79,86,79,86,86,86,86,,116171118120121123124125127128130131132134135137138139141 %N A186159调整了(f(i)和(g(j))在f(i)=g(j)之前与f(i)的联合秩序,其中f和g是三角数和八角数。A186274的补充。 %C A186159参见A186219了解调整后的关节秩序的讨论。 %e A186159首先,写出三角形和八角形数字: %e A186159 1..3..6…..10..15..21..28 %e A186159 1……..8……….21………%e A186159,然后用其等级替换它们,以三角数字排在八角形前的三角形数字来解决关系的问题: %e A186159A a=(1,3,4,4,6,6,7,7,8,10,11,13,…)=A186159。;%e A186159B=(2,5,9,9,12,15,19,19,22,26,……)=A186274.10;%t A186159(*调整后的联合排名,通式*)\\ %t A186159D=1/2;u=1/2;v=1/2;w=0;x=3;y=-2;z=0;;%t A18686159D=1/2;u=1/2;w=0;x=0 159 h[n_u]:=-y+(4倍(u*n^2+v*n+w-z-d)+y^2)^(1/2);10;%t A186159A[n[优]:=n+地板[h[n[n]/(2x)2]; %t A186159K[n[优]:=-v+(4u(4u(x*n ^ 2+y*y*n+z-w+d)+v ^2)^(1/2);10;%t A186159B[n[n[n]/(2u)];10;%t A186159表[a[n[n[n]/(2u)];%t A186159表[a[n],{n,1100}](*A186159 159*);%t A186159表[[[[[a[n[n[n],[[[第1 86159B[n],{n,1100}](*A186274*) %y A186159,参见A186219、A186274、A186275、A186276,%Y A186159 Cf.A000217(三角形数字);%Y A186159 Cf.A000567(八角数字);%K A186159 nonn %O A186159 1,2 %A A186159 %A A186159 2011年2月13日 内容可根据OEIS最终用户许可协议获取:http://OEIS.org/License