搜索: 编号:a237631
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A237631型
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| (n+1)X(2+1)0..2数组的数量,每个2X2子块的上中位数与其水平和垂直相邻块相差正好一。 |
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+0 1
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260, 636, 1220, 2356, 4500, 8594, 16448, 31672, 60362, 116180, 223768, 429680, 822032, 1584164, 3047968, 5848520, 11216480, 21603248, 41526472, 79692176, 153032384, 294531296, 565871200, 1086330032, 2087379872, 4014989408
(列表;图表;参考;听;历史;文本;内部格式)
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抵消
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1,1
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链接
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配方奶粉
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经验:当n>12时,a(n)=3*a(n-3)+10*a(n-4)-12*a(n7)-6*a(-n8)。
经验公式:2*x*(130+318*x+610*x^2+788*x^3-4*x^4-713*x^5-1410*x^6-1134*x^7-614*x*^8-324*x|9-68*x^10+5*x^11)/(1-3*x^3-10*x^4+12*x^7+6*x^8)-科林·巴克2018年10月24日
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例子
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n=5的一些解决方案:
..2..1..1....1..1..2....0..1..0....2..0..1....2..2..1....0..1..1....0..1..2
..0..2..1....0..2..1....2..0..0....2..1..0....1..0..0....0..0..2....1..2..1
..0..1..2…..2..1..0…..2..1..2…..0...0…..2..1..0…..1..2..1…..2...2...0..0
..0..0..0....0..0..0....0..0..2....0..1..2....1..2..0....2..1..0....1..0..1
..2..1..0....0..1..2....1..0..1....1..2..1....0..1..2....0..0..0....0..0..2
..2..0..2....0..2..1....1..2..2....2..1..1....0..0..0....0..1..2....1..2..0
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交叉参考
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关键词
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非n
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作者
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状态
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经核准的
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