搜索: 编号:a236739
|
|
A236739号
|
| 每个2X2子块的上中位数加上下中位数相等的(n+1)X(1+1)0..2数组的数目。 |
|
+0 1
|
|
|
81, 267, 833, 2907, 10233, 37467, 139201, 526395, 2012217, 7766523, 30188609, 118025307, 463513593, 1826935707, 7221598657, 28611883131, 113569804473, 451466339643, 1796832336449, 7158277169307, 28539550811769, 113856616625883
(列表;图表;参考;听;历史;文本;内部格式)
|
|
|
抵消
|
1,1
|
|
链接
|
|
|
配方奶粉
|
经验公式:a(n)=7*a(n-1)-2*a(n-2)-64*a(n3)+53*a(-n4)+229*a(v-5)-146*a(6-6)-364*a(7-7)+96*a(8-8)+192*a(m-9)。
经验公式:x*(81-300*x-874*x^2+2794*x^3+4345*x^4-7738*x^5-10020*x^6+5472*x^7+6720*x^8)/(1-x)*(1+x)*-科林·巴克,2018年10月21日
|
|
例子
|
n=5的一些解决方案:
..2..0....1..2....1..2....0..2....0..2....1..1....0..2....1..1....1..0....0..1
..0..0....0..1....2..1....2..1....1..1....0..1....0..2....1..2....2..1....2..0
..1..0....1..1....2..0....1..2....0..2....1..2....1..1....1..0....1..1....1..0
..0..0....1..2....1..2....2..0....1..1....1..1....1..0....1..2....1..1....2..0
..0..0....1..1....2..1....2..1....0..2....0..1....1..1....1..1....1..2....1..0
..1..0....0..1....2..1....2..0....1..1....1..1....1..0....1..0....0..1....2..0
|
|
交叉参考
|
|
|
关键词
|
非n
|
|
作者
|
|
|
状态
|
经核准的
|
|
|
搜索在0.003秒内完成
|