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| A233682型 |
| T（n，k）=（n+1）X（k+1）0..3数组的数量，每个2X2子块的边差平方和等于6（6使T（1,1）最大化） |
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9
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48, 184, 184, 648, 928, 648, 2440, 4448, 4448, 2440, 8712, 23568, 28544, 23568, 8712, 32456, 117744, 216592, 216592, 117744, 32456, 116872, 621904, 1500800, 2442208, 1500800, 621904, 116872, 432456, 3145968, 11482368, 25036784, 25036784
(列表;桌子;图表;参考;听;历史;文本;内部格式)
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抵消
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1,1
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评论
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表格开始
......48.......184.........648..........2440............8712.............32456
.....184.......928........4448.........23568..........117744............621904
.....648......4448.......28544........216592.........1500800..........11482368
....2440.....23568......216592.......2442208........25036784.........289389648
....8712....117744.....1500800......25036784.......365293440........6336415296
...32456....621904....11482368.....289389648......6336415296......169016684160
..116872...3145968....81243904....3057995568.....95799636288.....3879764059776
..432456..16510480...617735680...35239626640...1660462199232...103768584198400
.1565704..84078896..4416166400..377551693872..25500227965248..2432577744933760
.5768392.439062352.33345630720.4321333099024.438642994287168.64581965636210432
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链接
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配方奶粉
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k列的经验值：
k=1:a（n）=a（n-1）+12*a（n-2）-4*a（n3）-16*a（n-4）
k=2:[顺序10]
k=3:[订单17]
k=4:[订单45]
k=5:[顺序99]
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例子
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n=3k=4的一些解
..0..2..0..2..0....1..1..1..2..1....0..1..3..1..0....0..0..0..2..3
..0..1..0..1..0....0..2..0..2..3....0..2..2..2..2....1..2..1..2..1
..2..1..2..1..2....0..1..1..2..1....0..1..0..1..3....0..2..3..2..0
..2..3..3..1..3....2..2..3..2..3....0..2..2..2..2....0..1..3..1..1
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交叉参考
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关键词
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已批准
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