|
|
138076英镑 |
| 的签名版本A060187号通过p(t,x)=Exp[t*(1+2*x)]的Z变换获得。 |
|
0
|
|
|
1, -1, 1, 1, -6, 1, -1, 23, -23, 1, 1, -76, 230, -76, 1, -1, 237, -1682, 1682, -237, 1, 1, -722, 10543, -23548, 10543, -722, 1, -1, 2179, -60657, 259723, -259723, 60657, -2179, 1, 1, -6552, 331612, -2485288, 4675014, -2485288, 331612, -6552, 1, -1
(列表;桌子;图表;参考;听;历史;文本;内部格式)
|
|
|
偏移
|
0,5
|
|
链接
|
|
|
例子
|
{1},
{-1,
{1, -6, 1},
{-1, 23, -23, 1},
{1, -76, 230, -76, 1},
{-1, 237, -1682, 1682, -237, 1},
{1,-722,10543,-23548,10543,-722,1},
{-1, 2179, -60657, 259723, -259723, 60657, -2179, 1},
{1, -6552, 331612, -2485288, 4675014, -2485288, 331612, -6552, 1},
{-1, 19673, -1756340, 21707972, -69413294, 69413294, -21707972, 1756340, -19673, 1},
{1, -59038, 9116141, -178300904, 906923282, -1527092468, 906923282, -178300904, 9116141, -59038, 1}
|
|
数学
|
p[t_]=有效期[t]*x/(有效期[2*t]+x);
a=表[系数列表[FullSimplify[ExpandAll[(n!*(1+x)^(n+1)/x)*系列系数[系列[p[t],{t,0,30}],n]],x],{n,0,10}];
压扁[a]
|
|
交叉参考
|
|
|
关键词
|
|
|
作者
|
|
|
状态
|
经核准的
|
|
|
|