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A136453号 |
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A129065号用v=n代替v=1:递归多项式系数三角形。 |
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1, 0, 1, -1, -1, 1, 2, -3, -3, 1, 3, 20, -3, -6, 1, -44, -29, 80, 5, -10, 1, 145, -399, -354, 205, 30, -15, 1, 714, 3583, -1155, -1764, 385, 84, -21, 1, -12103, -4816, 29014, 1148, -5929, 532, 182, -28, 1, 51128, -202887, -163008, 132726, 23940, -15561, 420, 342, -36, 1, 520191, 2267207, -1085949, -1450530
(列表;桌子;图表;参考;听;历史;文本;内部格式)
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抵消
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1,7个
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评论
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行总和为:
{1, 1, -1, -3, 15, 3, -387, 1827, 8001, -172935, 735399}
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链接
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配方奶粉
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v=n;p(n,x)=(x+2*(n-1)^2-2*(v-1)*(n-1)-v+1)*p(n-1,x)-(n-1
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例子
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{1} ,
{0, 1},
{-1, -1, 1},
{2, -3, -3, 1},
{3, 20, -3, -6, 1},
{-44, -29, 80, 5, -10, 1},
{145, -399, -354,205, 30, -15, 1},
{714, 3583, -1155, -1764, 385, 84, -21, 1},
{-12103, -4816, 29014, 1148, -5929, 532, 182, -28, 1},
{51128, -202887, -163008, 132726, 23940, -15561, 420, 342, -36, 1},
{520191, 2267207, -1085949, -1450530, 397515, 120897, -34083, -390, 585, -45, 1}
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数学
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清除[p,v,x,n]p[-1,x]=0;p[0,x]=1;p[n,x_]:=p[n,x]=(x+2*(n-1)^2-2*(v-1)*(n-1)-v+1)*p[n-1,x]-(n-1)^2*(n-1-v)^2*p[n-2,x];v=n;a=Join[{{1}},Table[系数列表[p[n,x],x],{n,1,10}]];压扁[a]
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交叉参考
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关键词
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作者
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状态
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经核准的
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