本节专门研究解决方案的存在性。第一个结果借助格林函数将所提出的问题转化为等效积分形式。
定理3.1
让
\(磅/平方英寸{1}),\(psi{2})
是可积函数
\(u,v\in\mathrm{C}(\mathrm{J},\mathcal{X})
满足(1.1).然后,对于
\(3<西格玛),\(\beta,\rho\leq m\),\(m\geq 4),切换耦合系统的求解
$$\textstyle\begin{cases}{}^{c} D类^{\西格玛}[\phi_{p} D类^{\beta}u(t)]+\mathcal{F}(F)_{1} (t)\psi{1}(t,u(t),{}^{c} D类^{\rho}[\phi_{p} D类^{β}v(t)])=0,\quad t在\mathrm{J}中,\\{}^{c} D类^{\rho}[\phi_{p} D类^{\beta}v(t)]+\mathcal{F}(F)_{2} (t)\psi{2}(t,{}^{c} D类^{\西格玛}[\phi_{p} D类^{β}u(t)],v(t))=0,四t在\mathrm{J}中,([\phi_{p} D类^{\beta}u(0)])^{(j)}=0,\quad j=0,1,\dots,m-1,\\([\phi_{p} D类^{\beta}v(0)])^{(j)}=0,\quad j=0,1,\dots,m-1,\\I^{k-\beta{(u(0)$$
(3.1)
等价于积分方程
$$\begin{aligned}u(t)=&\int_{0}^{1}\mathcal{G}^{beta}(t,s)\phi_{q}\biggl(\nint_{0}^{s}(s-\tau)^{sigma-1}\mathcal{F}(F)_{1} (τ)\psi{1}\bigl(τ,u(\tau),{}^{c} D类^{\sigma}\bigl(\phi_{p} D类^{\beta}u(\tau)\bigr)\,d\tau\biggr)\,ds\end{对齐}$$
和
$$\begin{aligned}v(t)=&\int_{0}^{1}\mathcal{G}^{beta}(t,s)\phi_{q}\biggl(\int_}0}^}s}(s-\tau)^{sigma-1}\mathcal{F}(F)_{2} (τ)\psi{2}\bigl(τ,{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}u(\tau)\bigr),v(\tau)\bigr)\,d\tau\biggr)\,ds,\end{aligned}$$
哪里
\(\mathcal{G}^{beta}(t,s)\)
是格林函数,由
$$\mathcal{G}^{\beta}(t,s)=\textstyle\beart{cases}\frac{-(t-s)^{\beta-1}}{\varGamma(\beta)}-\frac{t^{\beta-1}(1-s)^{\beta-\delta-1}}{\varGamma(\beta)},&s\leq t\leq 1,t\in\mathrm{J}=(0,1),\\frac{-t^{\beta-1}(1-s)^{\beta-\delta-1}}伽马(β)},&t\leq s\leq 1。\结束{cases}$$
(3.2)
证明
让\(u,v\in\mathcal{C}(\mathrm{J},\mathcal{X})是…的解决方案(3.1),然后
$$\textstyle\begin{cases}{}^{c} D类^{\西格玛}[\phi_{p} D类^{\beta}u(t)]+\mathcal{F}(F)_{1} (t)\psi{1}(t,u(t),{}^{c} D类^{\rho}[\phi_{p} D类^{β}v(t)])=0,\quad t在\mathrm{J}中,\\{}^{c} D类^{\rho}[\phi_{p} D类^{\beta}v(t)]+\mathcal{F}(F)_{2} (t)\psi{2}(t,{}^{c} D类^{\西格玛}[\phi_{p} D类^{β}u(t)],v(t))=0,四t在\mathrm{J}中,([\phi_{p} D类^{\beta}u(0)])^{(j)}=0,\quad j=0,1,\dots,m-1,\\([\phi_{p} D类^{\beta}v(0)])^{(j)}=0,\quad j=0,1,\dots,m-1,\\I^{k-\beta{(u(0))=I^{k-\betaneneneep(v(0。\结束{cases}$$
自
$$ {}^{c} D类^{\sigma}(\phi_{p}\bigl(D^{\beta}u(t)\bigr)+\mathcal{F}(F)_{1} (t)\psi{1}\bigl(t,u(t),{}^{c} D类^{\rho}\bigl[\phi_{p} D类^{\beta}v(t)\bigr]\bigr)=0$$
(3.3)
哪里\(m-1<\西格玛<m\),\(m-1<\beta\leq m\),\(在数学中{J}).使用引理2.4,我们有
$$\begin{aligned}\phi_{p}\bigl(D^{beta}u(t)\bigr)=&-b_{0}-b_{1} t-b型_{2} t吨^{2}-\cdot-b_{m-1}吨^{m-1}\\&{}-\frac{1}{\varGamma(\sigma)}\int_{0}^{t}(t-s)^{\sigma-1}\mathcal{F}{1}(s)\psi_{1}\bigl(s,u(s),{}^{c} D类^{\rho}\bigl[\phi_{p} D类^{\beta}v(s)\bigr]\bigr)。\结束{对齐}$$
(3.4)
这个\((φ{p}(D^{beta}u(t)))^{(0)}|{t=0}=0\)暗示着\(-b{0}=0\)或\(b_{0}=0\)因此(3.4)成为
$$\begin{aligned}\phi_{p}\bigl(D^{beta}u(t)\bigr)=&-b_{1} t-b型_{2} t吨^{2}-\cdot-b_{m-1}吨^{m-1}\\&{}-\frac{1}{\varGamma(\sigma)}\int_{0}^{t}(t-s)^{\sigma-1}\mathcal{F}{1}(s)\psi_{1}\bigl(s,u(s),{}^{c} D类^{\rho}\bigl[\phi_{p} D类^{\beta}v(s)\bigr]\bigr)。\结束{对齐}$$
(3.5)
差异化(3.5)关于t吨,我们有
$$\开始{aligned}\bigl(\phi_{p}\bigle(D^{beta}u(t)\bigr)\biger)'=&-b_{1} -2b个_{2} t吨-\cdots-(m-1)b_{m-1}吨^{m-2}\\&{}-\frac{1}{\varGamma(\sigma-1)}\int_{0}^{t}(t-s)^{\sigma-2}\mathcal{F}(F)_{1} (s)\psi_{1}\bigl(s,u(s),{}^{c} D类^{\rho}\bigl[\phi_{p} D类^{\beta}v(s)\bigr]\bigr)。\结束{对齐}$$
使用条件\((φ_{p}(D^{\beta}u(t)))'|_{t=0}=0\)暗示着\(b{1}=0\)类似地,通过应用条件\((φ{p}(D^{beta}u(t)))^{(j)}|{t=0}=0\),我们得到\(b{j}=0\),\(所有j=2,3,点m)因此(3.4)成为
$$\begin{aligned}D^{\beta}u(t)=&-\phi_{p}^{-1}(I^{\sigma}\bigl(\mathcal{F}(F)_{1} (t)\psi{1}\bigl(t,u(t),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(t)\bigr)\biger)\\=&\phi_{q}(I^{\sigma}\mathcal{F}(F)_{1} (t)\psi{1}\bigl(t,u(t),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(t)\bigr)\biger)。\结束{对齐}$$
应用\(我^{\beta}\)并使用引理2.5,我们有
$$\开始{aligned}u(t)=&-d_{1} t吨^{\β-1}-d_{2} t吨^{\beta-2}-\cdots-d_{m} t吨^{\beta-m}\\&{}-\frac{1}{\varGamma(\beta)}\int_{0}^{t}(t-s)^{\beta-1}\phi_{q}(I^{\sigma}\mathcal{F}(F)_{1} (t)\psi{1}\bigl(t,u(t),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(t)\biger)\bigr)。\结束{对齐}$$
(3.6)
放\(I^{k-\beta}u(t)|_{t=0}=0\)对于\(k=2,3,点,米),我们获得\(d_{2}=d_{3}=\cdots=d_{m}=0\)、和使用\(D^{\delta}u(t)|_{t=1}=0\),我们得到
$$d_{1}=-\frac{\varGamma(\beta-\delta)}{\varGamma(\beta)}\phi _{q}(I^{\sigma}\mathcal{F}(F)_{1} (t)\psi{1}\bigl(t,u(t),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(t)\bigr)\biger)|_{t=1}$$
由此可见
$$开始{对齐}u(t)&=-\frac{1}{\varGamma(\beta)}\int_{0}^{t}(t-s)^{\beta-1}\phi_{q}\biggl(int_{0}^{s}(s-\tau)^{\sigma-1}\mathcal{F}(F)_{1} (τ)\psi{1}\bigl(τ,u(\tau),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\biger)\bigr)\,d\tau\biggr)\,ds\\&\quad{}-\frac{t^{\beta-1}}{\varGamma(\beta)}\int_{0}^{1}(1-s){F}(F)_{1} (τ)\psi{1}\bigl(τ,u(\tau),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\bigr)\,d\tau\biggr{F}(F)_{1} (τ)\psi{1}\bigl(τ,u(\tau),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\bigr)\,d\tau\biggr)\,ds.\end{aligned}$$
以类似的方式,我们可以得出这样的结论:
$$v(t)=\int_{0}^{1}\mathcal{G}^{beta}(t,s)\phi_{q}\biggl{F}(F)_{2} (τ)\psi{2}\bigl(τ,{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}u(\tau)\bigr),v(\teau)\biger)\,d\tau\biggr)\,ds$$
(3.7)
哪里\(\mathcal{G}^{beta}(t,s)\)是上面定义的格林函数。□
引理3.2
([8])
格林函数
\(\mathcal{G}^{beta}(t,s)\)
满足以下属性以下为:
-
\((\mathcal){P}(P)_{1})\)以下为:
-
\(\mathcal{G}^{beta}(t,s)>0\),\(\对于所有0<s \),\(t<1);
-
\((\mathcal){P}(P)_{2})\)以下为:
-
\(\mathcal{G}^{beta}(t,s)\)
是一个非递减函数,并且
\(最大值{t\in(0,1)}\mathcal{G}^{beta}(t,s)=\mathcal{G}^{beta}(1,s)\);
-
\((\mathcal){P}(P)_{3})\)以下为:
-
\(t^{\beta-1}\max_{t\in(0,1)}\mathcal{G}^{beta}(t,s)\leq\mathcal{G}^{beta}(t,s)\)
对于
\(0<s),\(t<1)。
我们引入以下假设:
-
\((\mathbf{高}_{1})\)以下为:
-
功能\(\psi_{1},\psi_2}:\mathrm{J}\times\mathcal{X}\times \mathcal{X}\rightarrow\mathcali{X}\)是连续的,并且\(对于所有u,v,\overline{u},\overline{v}\in\mathcal{X}\)和\(在数学中{J}),存在\(\mathcal{米}_{\psi_{1}},\mathcal{米}_{\psi_{2}},\mathcal{M'}{\psi{1}}这样的话
$$\bigl\Vert\psi_{1}(t,u,v)-\psi_}(t,\overline{u},\overrine{v})\bigr\Vert\leq\mathcal{米}_{\psi_{1}}\垂直u-\上划线{u}\垂直+\mathcal{M'}{\psi.{1}{\垂直v-\上划线}\垂直$$
和
$$\bigl\Vert\psi_{2}(t,u,v)-\psi_2}(t,\overline{u},\overrine{v})\bigr\Vert\leq\mathcal{米}_{\psi_{2}}\垂直u-\上划线{u}\垂直+\mathcal{M'}{\psi.{2}{\垂直v-\上划线}\垂直$$
-
\((\mathbf{高}_{2})\)以下为:
-
功能\(\psi_{1},\psi_2}:J\times\mathcal{X}\times\ mathcal}\rightarrow\mathcal{X}\)是完全连续的,\(对于所有u,v\in\mathcal{X})和\(在数学中{J}),存在非递减的连续线性函数\(\mu_{\psi_{1}},\mu_}\psi_2}}:\mathcal{R}^{+}\rightarrow\mathcal{R}\)这样的话
$$\bigl\Vert\psi_{1}(t,u,v)\bigr\Vert\leq\phi_{p}\bigl$$
和
$$\bigl\Vert\psi_{2}(t,u,v)\bigr\Vert\leq\phi_{p}\bigl$$
哪里
$$\begin{aligned}和\sup\bigl\{\mu_{\psi_{1}}(t),t\in\mathrm{J}\bigr\}=\mu_}\psi_1}},\qquad\sup\bigl\{\ mu_{\ psi_2}}}(t),t\in\mathrm{J}\bigr\}=\mu'{\psi{1}},\qquad\sup\bigl\{\mu'{\psi.{2}}。\结束{对齐}$$
-
\((\mathbf{高}_{3})\)以下为:
-
功能\(\mathcal{F}(F)_{1} ,\mathcal{F}_{2}:(0,1)\rightarrow\mathcal{X}\)非零且连续
$$\垂直\ mathcal{F}(F)_{1} \Vert=\max_{t\in\mathrm{J}}\Vert\mathcal{F}(F)_{1} \vert<\infty ^{+},\qquad\vert\mathcal{F}(F)_{2} \Vert=\max_{t\in\mathrm{J}}\Vert\mathcal{F}(F)_{2} \vert<\infty^{+}$$
让\(\mathcal{乙}_{r} \子集\mathbf{B}=\mathrm{C}是形式非负函数的锥
$$\马塔尔{乙}_{r} =\Bigl\{(u,v)\in\mathbf{B},\min_{t\in\mathrm{J}}\Bigl(u(t)+v(t)\bigr$$
和
$$\varOmega(r)=\biggl\{\bigl\Vert(u,v)\bigr\Vert<r,\Vert u\Vert<\frac{r}{2},\Vertv\Vert<\frac}{2{\biggr\},\ quad\partial\varOmega(r$$
考虑操作员\(\mathcal{H^{*}}=(\mathcal{H_{*}{{1},\mathca{H^}}{{2}):\mathcal{乙}_{r} /{(0,0)}\右箭头{\mathbf{B}}\),其中\(\mathcal{H^{*}}_{1}\),\(\mathcal{H^{*}}_{2}\)定义如下:
$$\begin{aligned}\textstyle\begin}{cases}\mathcal{H^{*}}_{1}(u,v)(t)\\quad=\int_{0}^{1}\mathcal{G}^{beta}(t,s)\phi_{q}(\frac{1}{\sigma}\int_}0}^}s}(s-\tau){1}(τ,u(τ),{}^{c} D类^{\rho}(\phi_{p} D类^{\beta}v(\tau))),d\tau),ds,\\mathcal{H^{*}}_2}(u,v)(t)\\quad=\int_{0}^{1}\mathcal}G}^{beta}(t,s)\phi_{q}(\frac{1}{\rho}\int_0}^s}(s-\tau)^{\rho-1}\mathcal{F}(F)_{2} (τ)\psi_{2}(τ,{}^{c} D类^{\sigma}(\phi_{p} D类^{β}u(\tau)),v(\tau)),d\tau),ds.\end{cases}\displaystyle\end{aligned}$$
(3.8)
定理3.3
假设
\((\mathbf{高}_{1})\)
到
\((\mathbf{高}_{3})\)
持有。然后(1.1)至少有一个解决方案。
证明
对于任何\((u,v)在上划线{(r{2})}/\varOmega(r{1}),并使用引理3.2,我们有
$$开始{对齐}[b]&\mathcal{H^{*}}_1}(u,v)(t)\\&\quad=\int_{0}^{1}\mathcal{G}^{beta}(t,s)\phi_{q}\biggl(\frac{1}{\sigma}\int_}0}^}s}(s-\tau){1}\bigl(τ,u(τ),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\bigr)\,d\tau \biggr)\,ds\\&&quad\leq\int _{0}^{1}\mathcal{G}^{\beta}(1,s)\phi _{q}\biggl(\frac{1}{\sigma}\int _{0}^{s}(s-\tau)^{\sigma-1}\mathcal{F}(F)_{1} (τ)\psi{1}\bigl(τ,u(\tau),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\bigr)\,d\tau\biggr)\,ds\end{对齐}$$
(3.9)
和
$$开始{对齐}[b]&\mathcal{H^{*}}_1}(u,v)(t)\\&\quad=\int_{0}^{1}\mathcal{G}^{beta}(t,s)\phi_{q}\biggl(\frac{1}{\sigma}\int_}0}^}s}(s-\tau){1}\bigl(τ,u(τ),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\biger)\bigr)\,d\tau\biggr)\,ds\\&\quad\geqt^{\beta-1}\int_{0}^{1}\mathcal{G}^{beta}(1,s)\\&\qquad{}\times\phi_{q}\biggl{F}(F)_{1} (τ)\psi{1}\bigl(τ,u(\tau),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\bigr)\,d\tau\biggr)\,ds.\end{aligned}$$
(3.10)
借助不平等(3.7)和(3.8),我们有
$$\mathcal{H^{*}}_{1}(u,v)(t)\geq t^{\beta-1}\bigl\Vert\mathcal{H^{*}}_{1}(u,v)(t)\bigr\Vert$$
(3.11)
同样,我们可以获得
$$\mathcal{H^{*}}_{2}(u,v)(t)\geqt^{\beta-1}\bigl\Vert\mathcal}H^{**}}_2}(u,v)(t)\bigr\Vert$$
(3.12)
组合(3.11)和(3.12),我们得到
$$\mathcal{H^{*}}(u,v)(t)\geqt^{\beta-1}\bigl\Vert\mathcal}(u^{*{}})(t,v)\bigr\Vert$$
因此\(\mathcal{H^{*}}:\上划线{\varOmega(r_{2})}/\varOmega(r_1})\rightarrow{\mathbf{B}}\)已关闭。
关于算子的一致有界性\(\mathcal{H^{*}}\),我们认为
$$开始{对齐}和\bigl\Vert\mathcal{H^{*}}(u,v)(u,v)(t)\vert+\sup_{t\in\mathrm{J}}\bigl\vert\mathcal{H^{*}}_2}(u,v)(t)\bigr\vert\\&\quad\leq\sup_}\tin\mathr m{J{}\biggl\vert\int_{0}^{1}\mathcal}G}^{beta}(t,s)\&\qquad\}}\times\phi_{q}\bigl(\frac{1}{\varGamma(\sigma)}\int_{0}^{s}(s-\tau)^{\sigma-1}\mathcal{F}(F)_{1} (τ)\psi{1}\bigl(τ,u(\tau),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\biger)\bigr)\,d\tau\biggr)\,ds\biggr\vert\\&\qquad{}+\sup_{t\in\mathrm{J}}\biggl\vert\int_{0}^{1}\mathcal{G}{\beta}(t,s)\\&\qquid{}\times\phi_{q}\bigl(\frac{1}{\varGamma(\rho)}\int_{0}^{s}(s-\tau)^{\rho-1}\mathcal{F}(F)_{2} (τ)\psi{2}\bigl(τ,{}^{c} D类^{\sigma}\bigl(\phi_{p} D类^{\beta}u(\tau)\bigr),v(\teau)\biger)\,d\tau\biggr)\,ds\biggr\vert\\&\quad\leq\int_{0}^{1}\bigl\vert\mathcal{G}^{beta}(1,s)\biger\vert\\&\qquad{}\times\phi_{q}\biggl(\frac{1}{\varGamma(\sigma)}\int_0}^s}(s-\tau)^{\sigma-1}\bigl\vert\mathcal{F}(F)_{1} (\tau)\bigr\Vert\bigl\Vert\psi_{1}\bigl(\tau,u(\tau),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\biger)\bigr\Vert\,d\tau\biggr)^{\rho-1}\bigl\Vert\mathcal{F}(F)_{2} (tau)\bigr\Vert\bigl\Vert\psi_{2}\bigl(\tau,{})^{c} D类^{\sigma}\bigl(\phi_{p} D类^{β}u(\tau),v(\tao)\biger)\bigr\Vert\,d\tau\biger \\&\qquad{}\times\Vert\mathcal{F}(F)_{1} 垂直^{q-1}\biggl(压裂{F}(F)_{2} \垂直\垂直v\垂直}{1-\Vert\mathcal{F}(F)_{1} \Vert\Vert\mathcal(垂直){F}(F)_{2} \Vert\mu'{\psi{1}}\mu{\psi.{2}}\biggr)\\&\qquad{}+\biggl(\frac{1}{\varGamma(\beta+1)}-\frac}{\varGamma四边形{}\times\Vert\mathcal{F}(F)_{2} 垂直^{q-1}\biggl(压裂{F}(F)_{1} \垂直\垂直u\垂直+\mu_{\psi_{2}}\垂直v\Vert}{1-\Vert\mathcal{F}(F)_{1} \Vert\Vert\mathcal(垂直){F}(F)_{2} \Vert\mu’_{\psi _{1}}\mu _{\psi _{2}}}\biggr)\\&&quad=\biggl(\frac{1}{\varGamma(\beta+1)}-\frac{1}{\varGamma(\beta-\delta)\varGamma(\beta)}\biggr)\biggl[\biggl(\frac{1}{\varGamma(\sigma+1)}\biggr)^{q-1}\\&&\qquad{}\times\Vert\mathcal{F}(F)_{1} 垂直^{q-1}\biggl(压裂{F}(F)_{2} \垂直\垂直v\垂直}{1-\Vert\mathcal{F}(F)_{1} \Vert\Vert\mathcal(垂直){F}(F)_{2} \Vert\mu'{\psi{1}}\mu_{\psi.{2}}\biggr)\\&\qquad{}+\biggl(\frac{1}{\varGamma(\rho+1)}\bigbr)^{q-1}\Vert\mathcal{F}(F)_{2} 垂直^{q-1}\biggl(压裂{F}(F)_{1} \垂直\垂直u\垂直+\mu'_{\psi_{2}}\垂直v\垂直}{1-\Vert\mathcal{F}(F)_{1} \Vert\Vert\mathcal(垂直){F}(F)_{2} \垂直\mu’{\psi{1}}\mu{\psi{2}}\biggr)\biggr]\\&\quad<\infty。\结束{对齐}$$
因此\(\mathcal{H^{*}}\)是一致有界运算符。
现在,我们显示操作符\(\mathcal{H^{*}}\)是连续和紧凑的。因此,我们构造了一个序列\(xi{n}=(u{n},v{n})这样的话\((u{n},v{n})\右箭头(u,v)\)作为\(n\rightarrow\infty\)因此,我们有
$$开始{aligned}和\bigl\Vert\bigl(\mathcal{H^{*}}(u_{n},v_{n{)-\mathcal{H^}(u,v)\bigr bigl(\mathcal{H^{*}}_{1},\mathcal{H^}}_2}\bigr)(u,v))\bigr\|\\&\quad\leq\bigl\Vert\bigl(u,v)\biger)\bigr\Vert+\bigl\Vert\bigl t,s)\\&\qquad{}\times\phi_{q}\biggl(\frac{1}{\varGamma(\sigma)}\int_{0}^{s}(s-\tau)^{\sigma-1}\mathcal{F}(F)_{1} (\tau)\psi_{1}\bigl(\tau,u_{n}(\tau),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v_{n}(\tau)\bigr)\,d\tau\biggr)\,ds\\&\qquad{}-\int_{0}^{1}\mathcal{G}^{beta}(t,s)\phi_{q}\biggl{F}(F)_{1} (τ)\psi{1}\bigl(τ,u(\tau),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\biger)\bigr)\,d\tau\biggr)\,ds\biggr\vert\\&\qquad{}+\sup_{t\in\mathrm{J}}\biggl\vert\int_{0}^{1}\mathcal{G}{\beta}(t,s)\\&\qquid{}\times\phi_{q}\bigl(\frac{1}{\varGamma(\rho)}\int_{0}^{s}(s-\tau)^{\rho-1}\mathcal{F}(F)_{2} (τ)\psi{2}\bigl(τ,{}^{c} D类^{\sigma}\bigl(\phi_{p} D类^{β}u_{n}(\tau)\bigr),v_{n}(\t au)\ bigr \mathcal公司{F}(F)_{2} (τ)\psi{2}\bigl(τ,{}^{c} D类^{\sigma}\bigl(\phi_{p} D类^{\beta}u(\tau)\bigr),v(\tau)\biger)\,d\tau\biggr)\,ds\biggr\vert\\&\quad\leq\int_{0}^{1}\bigl\vert\mathcal{G}^{beta}(t,s)\biger\vert\\\&\qquad{}\times\biggl\vert\phi_{q}\biggl(\frac{1}{\varGamma(\sigma)}\nint_{0}^{s}(s-\tau)^{\sigma-1}\mathcal{F}(F)_{1} (\tau)\psi_{1}\bigl(\tau,u_{n}(\tau),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v{n}(\tau)\bigr)\,d\tau\biggr)\,ds\\&\qquad{}-\phi_{q}\biggl(\frac{1}{\varGamma(\sigma)}\int_{0}^{s}(s-\tau{F}(F)_{1} (τ)\psi{1}\bigl(τ,u(\tau),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\biger)\bigr)\,d\tau\biggr}\int_{0}^{s}(s-\tau)^{\rho-1}\mathcal{F}(F)_{2} (τ)\psi{2}\bigl(τ,{}^{c} D类^{\sigma}\bigl(\phi_{p} D类^{β}u_{n}(\tau)\bigr),v_{n{(\teau)\biger)\,d\tau\biggr)\,ds\\&\qquad{}-\phi_{q}\biggl(\frac{1}{varGamma(\rho)}\int_{0}^{s}(s-\tau{F}(F)_{2} (τ)\psi{2}\bigl(τ,{}^{c} D类^{\sigma}\bigl(\phi_{p} D类^{\beta}u(\tau)\bigr),v(\tau)\biger)\,d\tau\biggr)\,ds\biggr\Vert\biggr\}\\&\quad\leq(q-1)\varrho^{2}\int_{0}^{1}\bigl\Vert\mathcal{G}(t,s)\biger\Vert\&\qquad{}\times\biggl\frac{1}\varGamma(\sigma)}\int_{0}^{s}(s-\tau)^{\sigma-1}\bigl\Vert\mathcal{F}(F)_{1} (\tau)\bigr\Vert\bigl\Vert\psi_{1}\bigr(\tau,u_{n}(\tao),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v{n}(\tau)\biger)^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\biger)\bigr\Vert\,d\tau\bigr)\,ds\\&\qquad{}+\frac{1}{\varGamma(\rho)}\int_{0}^{s}(s-\tau)^{\rho-1}\bigl\Vert\mathcal{F}(F)_{2} (tau)\bigr\Vert\bigl\Vert\psi_{2}\bigl(\tau,{})^{c} D类^{\sigma}\bigl(\phi_{p} D类^{\beta}u_{n}(\tau)\bigr),v_{n{(\teau)\biger)\\&\qquad{}-\psi_{2}\bigl(\tao,^{{c}}D^{\sigma}\bigle(\phi_{p} D类^{\beta}u(\tau),v(\tau)\bigr)\bigr\Vert\,d\tau\bigr)\,ds\biggr\}\&&quad\leq(q-1)\varrho^{2}\int _{0}^{1}\bigl\Vert\mathcal{G}^{\beta}(t,s)\bigr\Vert\biggl\{\frac{\mathcal{米}_{\psi_{1}}\垂直\mathcal{F}(F)_{1} \垂直\垂直u_{n} -u个\Vert+\mathcal{M}'_{\psi_{1}}\mathcal{M}'{\psi.{2}}\Vert\mathcal{F}(F)_{1} \Vert\Vert\mathcal(垂直){F}(F)_{2} \垂直\垂直v_{n} -v型\垂直}{\varGamma(\sigma+1)}\\&\qquad{}+\frac{\mathcal{米}_{\psi_{1}}\mathcal{米}_{\psi_{2}}\Vert\mathcal{F}_{1}\Vert\mathcal{F}(F)_{2} \ | \垂直u_{n} -u个\Vert+\mathcal{M}'_{\psi_{2}}\|\mathcal{F}(F)_{2} \ | \垂直v_{n} -v型\Vert}{\varGamma(\rho+1)}\biggr\}\\&\quad\rightarrow 0,\quad_text{作为$n\rightarror\infty$.}\end{aligned}$$
因此,\(\|\mathcal{H^{*}}(u_{n},v_{n{)-\mathcal{H^}},(u,v)\|\rightarrow 0\)作为\(n\rightarrow\infty\).因此\(\mathcal{H^{*}}\)是连续的。
对于等连续性,取\(\upsilon_{1},\upsillon_{2}\in\mathrm{J}\)具有\(\upsilon _{1}<\upsilon _{2}\),对于任何\((u,v)\ in \ varOmega(r)\),我们有
$$开始{对齐}和\bigl\Vert\bigl(\mathcal{H^{*}}(u,v)(\upsilon_{1}{H^{*}}_{1}(u,v)(\upsilon_{2})\biger-\mathcal{H^{*}}_2}(u,v)(\upsilon_{2})\biger)\bigr\Vert\\&\quad=\sup_{t\in\mathrm{J}}\biggl\Vert\int_{0}^{1}\mathcal{G}{beta}(\upssilon_{1},s)\phi_{q}\bigl(\frac{1}{\varGamma(\sigma)}\int_{0}^{s}(s-\tau)^{sigma-1}\mathcal{F}(F)_{1} (τ)\psi{1}\bigl(τ,u(\tau),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\bigr)\,d\tau\biggr)\,ds\\&\qquad{}-\int_{0}^{1}\mathcal{G}^{\beta}(\upsilon_{2},s)\phi_{q}\biggl(\frac{1}{\varGamma(\sigma{F}(F)_{1} (τ)\psi{1}\bigl(τ,u(\tau),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\bigr)\,d\tau\biggr)\,ds\biggr\vert\\&\qquad{}+\sup_{t\in\mathrm{J}}\biggl\vert\int _{0}^{1}\mathcal{G}^{\beta}(\tau_{1},s)\\&\qquad{}\times\phi{q}\biggl(\frac{1}{\varGamma(\rho)}\int _{0}^{s}(s-\tau)^{\rho-1}\数学{F}(F)_{2} (τ)\psi{1}\bigl(τ,{}^{c} D类^{\sigma}\bigl(\phi_{p} D类^{\beta}u(\tau),v(\tao)\bigr)\,d\tau\biggr)\,ds\\&\qquad{}-\int_{0}^{1}\mathcal{G}^{beta}(\upsilon_{2},s)\phi_{q}\biggl马查尔{F}(F)_{2} (τ)\psi{1}\bigl(τ,{}^{c} D类^{\sigma}\bigl(\phi_{p} D类^{β}u(\tau),v(\teau)\bigr)\biger)\,d\tau\biggr gl(\frac{1}{\varGamma(\sigma)}\int_{0}^{s}(s-\tau)^{\sigma-1}\vert\mathcal{F}(F)_{1} \Vert\bigl\Vert\psi_{1}\bigl(\tau,u(\tao),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\biger)\bigr\Vert\,d\tau\biggr)\,ds\\&\qquad{}+\int_{0}^{1}\bigl\Vert\mathcal{G}^{beta}c{1}{\varGamma(\rho)}\int_{0}^{s}(s-\tau)^{\rho-1}\Vert\mathcal{F}(F)_{2} \Vert\bigl\Vert\psi_{1}\bigl(\tau,{}^{c} D类^{\sigma}\bigl(\phi_{p} D类^{β}u(\tau),v(\tao)\biger)\biger\Vert\,d\tau\biggr)\,ds\\&\quad\leq\biggl(\frac{\Vert\upsilon_{1}^{\beta}-\upsilon_{2}^{\ beta}\Vert}{\varGamma(\beta+1)}+\frac}\Vert\opsilon_ \beta-1}\Vert}{\varGamma(\beta-\delta)\varGamma(\beta+1)}\biggr)\biggl[\frac{1}{\varGamma(\sigma+1)}\biggr]^{q-1}\&&\qquad{}\times\Vert\mathcal{F}(F)_{1} 垂直^{q-1}\biggl(压裂{F}(F)_{2} \垂直\垂直v\垂直}{1-\Vert\mathcal{F}(F)_{1} \Vert\Vert\mathcal(垂直){F}(F)_{2} 垂直\mu'{\psi{1}}\mu{\psi.{2}}\biggr){\varGamma(\beta-\delta)\varGarma(\beta+1)}\biggr)\biggl[\frac{1}{\var伽玛(\rho+1)}\ biggr]^{q-1}\\&\qquad{}\times\Vert\mathcal{F}(F)_{2} 垂直^{q-1}\biggl{F}(F)_{1} \Vert\Vert\mathcal(垂直){F}(F)_{2} \Vert\mu'{\psi_{1}}\mu_{\psi.{2}}\biggr)。\结束{对齐}$$
这意味着\(\|\mathcal{H^{*}}(u,v)(\upsilon_{1})-\mathcal{H^}}作为\(\upsilon_{1}\rightarrow\upsillon_{2}\).因此\(\mathcal{H^{*}}\)相对紧凑。根据Arzelä–Ascolli定理,\(\mathcal{H^{*}}\)是紧凑的,因此是完全连续的算子。
现在让我们定义一个集合
$$\mathrm{W}=\bigl\{(u,v$$
我们将证明W是有界的。相反,假设W是无界的。让\((u,v)\in\mathrm{W}\)这样的话\(\|(u,v)\|=\mathcal{K}\rightarrow\infty\).但是
$$\begin{aligned}\bigl\Vert(u,v)\bigr\Vert=&\bigl\ Vert\lambda\mathcal{H}(u,v)\biger\Vert\\\leq&\bigle\Vert\mathcal}(u,v)\ bigr\Vert\\\leq&\biggl(\frac{1}{\varGamma(\beta+1)}-\frac}{1}{\varGamma(beta-\delta)\varGamma(\beta)}\big gr)\\&{}\times\biggl[\biggl(\frac{1}{\varGamma(\sigma+1)}\biggr)^{q-1}\Vert\mathcal{F}(F)_{1} 垂直^{q-1}\biggl(压裂{F}(F)_{2} \垂直\垂直v\垂直}{1-\Vert\mathcal{F}(F)_{1} \Vert\Vert\mathcal(垂直){F}(F)_{2} \Vert\mu'{\psi{1}}\mu_{\psi.{2}}\biggr)\\&{}+\biggl(\frac{1}{\varGamma(\rho+1)}\bigbr)^{q-1}\Vert\mathcal{F}(F)_{2} 垂直^{q-1}\biggl(压裂{F}(F)_{1} \垂直\垂直u\垂直+\mu'_{\psi_{2}}\垂直v\垂直}{1-\Vert\mathcal{F}(F)_{1} \Vert\Vert\mathcal(垂直){F}(F)_{2} \Vert\mu'_{\psi_{1}}\mu_{\psi _{2}}}\biggr)\biggr]。\结束{对齐}$$
这意味着
$$开始{aligned}\bigl\Vert(u,v)\bigr\Vert\leq&\biggl(\frac{1}{\varGamma(\beta+1)}-\frac}{\varGamma{F}(F)_{1} 垂直^{q-1}\biggl(压裂{F}(F)_{2} \垂直\垂直v\垂直}{1-\Vert\mathcal{F}(F)_{1} \Vert\Vert\mathcal(垂直){F}(F)_{2} \Vert\mu'{\psi{1}}\mu_{\psi.{2}}\biggr)\\&{}+\biggl(\frac{1}{\varGamma(\rho+1)}\bigbr)^{q-1}\Vert\mathcal{F}(F)_{2} 垂直^{q-1}\biggl(压裂{F}(F)_{1} \垂直\垂直u\垂直+\mu'_{\psi_{2}}\垂直v\垂直}{1-\Vert\mathcal{F}(F)_{1} \Vert\Vert\mathcal(垂直){F}(F)_{2} \Vert\mu’_{\psi_{1}}\mu _{\psi_{2}}}\biggr)\biggr],\end{aligned}$$
同等地
$$开始{对齐}1\leq&\frac{1}{\Vert(u,v)\Vert}\biggl(\frac{1'{\varGamma(\beta+1)}-\frac{1}}{\varGamma(\ beta-\delta)\varGamma(\beta盐酸{F}(F)_{1} 垂直^{q-1}\biggl(压裂{F}(F)_{2} \垂直\垂直v\垂直}{1-\Vert\mathcal{F}(F)_{1} \Vert\Vert\mathcal(垂直){F}(F)_{2} \Vert\mu'{\psi{1}}\mu_{\psi.{2}}\biggr)\\&{}+\biggl(\frac{1}{\varGamma(\rho+1)}\bigbr)^{q-1}\Vert\mathcal{F}(F)_{2} 垂直^{q-1}\biggl(压裂{F}(F)_{1} \垂直\垂直u\垂直+\mu'_{\psi_{2}}\垂直v\垂直}{1-\Vert\mathcal{F}(F)_{1} \Vert\Vert\mathcal(垂直){F}(F)_{2} \Vert\mu'{\psi{1}}\mu_{\psi.{2}}\biggr)\biggr]\\=&\frac{1}{\mathcal{K}}\biggl{\varGamma(\sigma+1)}\biggr)^{q-1}\Vert\mathcal{F}(F)_{1} 垂直^{q-1}\biggl(压裂{F}(F)_{2} \垂直\垂直v\垂直}{1-\Vert\mathcal{F}(F)_{1} \Vert\Vert\mathcal(垂直){F}(F)_{2} \Vert\mu'{\psi{1}}\mu_{\psi.{2}}\biggr)\\&{}+\biggl(\frac{1}{\varGamma(\rho+1)}\bigbr)^{q-1}\Vert\mathcal{F}(F)_{2} 垂直^{q-1}\biggl(压裂{F}(F)_{1} \垂直\垂直u\垂直+\mu'_{\psi_{2}}\垂直v\垂直}{1-\Vert\mathcal{F}(F)_{1} \Vert\Vert\mathcal(垂直){F}(F)_{2} \Vert\mu'_{\psi_{1}}\mu_{\psi _{2}}\biggr)\biggr]\\rightarrow&0\quad\text{as}\mathcal{K}\rightarror\infty。\结束{对齐}$$
这是一个矛盾。最终W是有界的,因此由引理2.7操作员\(\mathcal{H}\)中至少有一个固定点\(\varOmega(r_{2})/\varOmega(r_1})\),这是耦合系统的解决方案(1.1).
因此,通过引理2.9, (1.1)至少有一种解决方案。□
控制非线性函数的增长界\(磅/平方英寸{1}),\(psi{2})然后继续下一个结果,我们需要以下高度函数。让
$$\begin{aligned}\textstyle\begin{cases}\Im _{\max _{t\in\mathrm{J},x>0}}}(t,x)=\ max\{\{\psi _{1},\ psi _{2}\}:t^{\beta-1}x\ leq(u,v)\ leq x\},\\\Im _{\mamin _{t\in\mathrm{J},x>0}}}(t,x)=\ min\{\{\psi _{1},\ psi _{2}\}:t^{\beta-1}x\leq(u,v)\leq x\}。\结束{cases}\displaystyle\end{aligned}$$
(3.13)
定理3.4
假设
\((\mathbf{高}_{1})\)
到
\((\mathbf{高}_{3})\)
持有,并且存在
\(r^{*},\hbar\in \mathcal{r}^{+}\)
满足以下条件之一以下为:
-
\((\我{1})\)以下为:
-
$$\hbar\leq\int_{0}^{1}\mathcal{G}^{beta}(1,s)\phi_{q}\biggl(\frac{1}{varGamma(\sigma)}\int_}0}^}s}(s-\tau)^{sigma-1}\mathcal{F}(F)_{1} (τ)\Im_{\min}\bigl(τ,\hbar,{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\bigr)\,d\tau\biggr)\,ds<\infty^{+}$$
和
$$\int_{0}^{1}\mathcal{G}^{beta}(1,s)\phi_{q}\biggl{F}(F)_{1} (\tau)\Im _{\max}\bigl(\tau,r^{*},{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\bigr)\,d\tau\biggr)\,ds\leqr^{*}$$
-
\((Im _{2})\)以下为:
-
$$\int_{0}^{1}\mathcal{G}^{beta}(1,s)\phi_{q}\biggl{F}(F)_{1} (τ)\Im_{max}\bigl(τ,hbar,{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\bigr)\,d\tau\biggr)\,ds<\hbar$$
和
$$r^{*}\leq\int _{0}^{1}\mathcal{G}^{\beta}(1,s)\phi _{q}\biggl(\frac{1}{\varGamma(\sigma)}\int _{0}^{s}(s-\tau)^{\sigma-1}\mathcal{F}(F)_{1} (τ)\Im_{\min}\bigl(τ,r^{*},{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\bigr)\,d\tau\biggr)\,ds<\infty^{+}$$
-
\((\我{3})\)以下为:
-
$$\hbar\leq\int_{0}^{1}\mathcal{G}^{beta}(1,s)\phi_{q}\biggl(\frac{1}{varGamma(\sigma)}\int_}0}^}s}(s-\tau)^{sigma-1}\mathcal{F}(F)_{2} (τ)\Im_{min}\bigl(τ,{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}u(\tau),\hbar\bigr)\bigr)\,d\tau\biggr)\,ds<\infty^{+}$$
和
$$\int_{0}^{1}\mathcal{G}^{beta}(1,s)\phi_{q}\biggl{F}(F)_{2} (τ)\Im_{max}\bigl(τ,{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}u(\tau)\bigr),r^{*}\biger)\,d\tau\biggr)\,ds\leqr^{*}$$
-
\((\Im_{4})\)以下为:
-
$$\int_{0}^{1}\mathcal{G}^{beta}(1,s)\phi_{q}\biggl{F}(F)_{2} (τ)\Im_{max}\bigl(τ,{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}u(\tau)\bigr),\hbar\biger)\,d\tau\biggr)\,ds<\hbar$$
和
$$r^{*}\leq\int _{0}^{1}\mathcal{G}^{\beta}(1,s)\phi _{q}\biggl(\frac{1}{\varGamma(\sigma)}\int _{0}^{s}(s-\tau)^{\sigma-1}\mathcal{F}(F)_{2} (τ)\Im_{min}\bigl(τ,{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}u(\tau)\bigr),r^{*}\biger)\,d\tau\biggr)\,ds<\infty^{+}$$
然后是问题(1.1)具有非负解
\((u^{*},v^{*{)在\mathcal中{乙}_{r} \times\mathcal时间{乙}_{r} \),以便
\(\hbar\leq\|(u^{},v^{*})\|\leqr^{*{})。
证明
在不失一般性的情况下,我们只采取\((\我{1})\)和\((Im _{2})\).如果\((u,v)\ in \ partial \ varOmega(\hbar)\),然后\(\|(u,v)\|=\hbar\)和\(t^{\beta-1}\hbar\leq(u,v)\leq\hbar\),\(在数学中{J}).签署人(3.13)我们有
$$\begin{aligned}&&bigl\Vert\mathcal{H}^{*}(u,v)(t)\bigr\Vert\\&&quad=\bigl\Vert\bigl(\mathcal{H}^{*}_{1},\mathcal{H}^{*}_{2}\bigr)(u,v)(t)\bigr\Vert\\&&quad=\sup_{t\in\mathrm{J}}\int _{0}^{1}\mathcal{G}^{\beta}(t,s)\phil{q}\biggl(\frac{1}{\varGamma(\sigma)}\int_{0}^{s}(s-\tau)^{\sigma-1}\mathcal{F}(F)_{1} (τ)\psi{1}\bigl(τ,u(\tau),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\bigr)\,d\tau\biggr)\,ds\\&\qquad{}+\sup_{t\in\mathrm{J}}\int_{0}^{1}\mathcal{G}^{beta}(t,s)\phi_{q}\biggl(\frac{1}{\varGamma(\rho)}\int_0}^{s}(s-\tau)^{\rho-1}\mathcal公司{F}(F)_{2} (τ)\psi{2}\bigl(τ,{}^{c} D类^{\sigma}\bigl(\phi_{p} D类^{\beta}u(\tau)\bigr),v(\tao)\bigr)\,d\tau\biggr)\,ds\\&\quad\geq t^{\beta-1}\int_{0}^{1}\mathcal{G}^{beta}(1,s)\phi_{q}\biggl盐酸{F}(F)_{1} (τ)\psi{1}\bigl(τ,u(\tau),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\biger)\bigr)\,d\tau\biggr)\,ds\\&\qquad{}+t^{\beta-1}\int_{0}^{1}\mathcal{G}^{beta}(1,s)\\&\q quad{{}\ times\phi_{q}\biggl(\frac{1}{\varGamma(\rho)}\int_{0}^{s}(s-\tau)^{\rho-1}\马塔尔{F}(F)_{2} (τ)\psi{2}\bigl(τ,{}^{c} D类^{\sigma}\bigl(\phi_{p} D类^{\beta}u(\tau)\bigr),v(\tau)\biger)\,d\tau\biggr)\,ds\\&\quad\geq\int_{0}^{1}\mathcal{G}^{beta}(1,s)\phi_{q}\biggl(\frac{1}{\varGamma(\sigma)}\int_0}^s}(s-\tau{F}(F)_{1} (τ)\Im_{min_{t\in\mathrm{J}}}\bigl(τ,hbar,{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\bigr)\bigr]\,d\tau\biggr)\,ds\\&\qquad{}+\int_{0}^{1}\mathcal{G}^{\beta}(1,s)\phi_{q}\biggl(\frac{1}{\varGamma(\rho)}\int_}^{s}(s-\tau)^{\rho-1}\bigl[\mathcal{F}(F)_{2} (τ)\Im_{min_{t\in\mathrm{J}}}\bigl(τ,{}^{c} D类^{\sigma}\bigl(\phi_{p} D类^{\beta}u(\tau)\bigr),\hbar\biger)\biger]\,d\tau\biggr)\,ds\\&\quad\geq\frac{\hbar}{2}+\frac}\hbar{2}=\hbar=\bigl\Vert(u,v)\bighr\Vert。\结束{对齐}$$
因此
$$\bigl\Vert\mathcal{H}^{*}(u,v)(t)\bigr\Vert\geq\hbar=\bigl\ Vert(u,v)\biger\Vert$$
什么时候?\((u,v)\ in \ partial \ varOmega(r^{*})\),然后\(\ |(u,v)\ |=r^{*}\),和依据(3.13),\(t^{\beta-1}r^{*}\leq(u,v)\leqr^{**}\),我们有\(\Im_{max_{t\in\mathrm{J}}}\geq\{psi{1},\psi{2}),因此
$$开始{对齐}和\bigl\Vert\mathcal{H}^{*}(u,v)数学{G}^{beta}(t,s)\phi_{q}\biggl(\frac{1}{\varGamma(\sigma)}\int_{0}^{s}(s-\tau)^{\sigma-1}\mathcal{F}(F)_{1} (τ)\psi{1}\bigl(τ,u(\tau),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\bigr)\,d\tau \biggr)\,ds\\&&\qquad{}+\max_{t\in\mathrm{J}}\int _{0}^{1}\mathcal{G}^{\beta}(t,s)\\&&\qquad{}\times\phi{q}\biggl(\frac{1}{\varGamma(\rho)}\int _{0}^{s}(s-\tau)^{\rho-1}\mathcal{F}(F)_{2} (τ)\psi{2}\bigl(τ,{}^{c} D类^{\sigma}\bigl(\phi_{p} D类^{\beta}u(\tau)\bigr),v(\tao)\bigr)\,d\tau\biggr)\,ds\\&\quad\leq t^{\beta-1}\int_{0}^{1}\mathcal{G}^{beta}(1,s)\phi_{q}\biggl盐酸{F}(F)_{1} (τ)\psi{1}\bigl(τ,u(\tau),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\biger)\bigr)\,d\tau\biggr)\,ds\\&\qquad{}+t^{\beta-1}\int_{0}^{1}\mathcal{G}^{beta}(1,s)\\&\q quad{{}\ times\phi_{q}\biggl(\frac{1}{\varGamma(\rho)}\int_{0}^{s}(s-\tau)^{\rho-1}\马塔尔{F}(F)_{2} (τ)\psi{2}\bigl(τ,{}^{c} D类^{\sigma}\bigl(\phi_{p} D类^{\beta}u(\tau)\bigr),v(\tau)\biger)\,d\tau\biggr)\,ds\\&\quad\leq\int_{0}^{1}\mathcal{G}^{beta}(1,s)\phi_{q}\biggl(\frac{1}{\varGamma(\sigma)}\int_0}^s}(s-\tau{F}(F)_{1} (τ)\Im_{max_{t\in\mathrm{J}}}\bigl(τ,r^{*},{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\biger)\bigr]\,d\tau\biggr)\,ds\\&\qquad{}+\int_{0}^{1}\mathcal{G}^{\beta}(1,s)\\&\quad{{}\times\phi_{q}\biggl(\frac{1}{\varGamma(\rho)}\int_}^{s}(s-\tau)^{\rho-1}\bigl[\mathcal公司{F}(F)_{2} (τ)\Im_{max_{t\in\mathrm{J}}}\bigl(τ,{}^{c} D类^{\sigma}\bigl(\phi_{p} D类^{\beta}u(\tau)\bigr),r^{*}\biger)\biger]\,d\tau\biggr。\结束{对齐}$$
因此
$$\bigl\Vert\mathcal{H}^{*}(u,v)(t)\bigr\Vert\geq\hbar=\bigl\ Vert(u,v)\biger\Vert$$
结合这些不平等,我们说\({\mathcal{H}^{*}}\)间隔中有一个固定点\([\hbar,r^{*}]\),说吧\((u^{*},v^{*{)在\上划线{\varOmega(r^{*neneneep)}/\varOmega(\hbar)\中,因此\(\hbar\leq\|(u^{},v^{*})\|\leqr^{*{})。接下来我们将展示\((u^{*},v^{*{)\)是的非负解\(在数学中{J})作为
$$\开始{aligned}u^{*}(t)=&\int_{0}^{1}\mathcal{G}^{beta}(t,s)\phi_{q}\biggl(\frac{1}{\varGamma(\sigma)}\int_}0}^s}(s-\tau)^{\sigma-1}\mathcal{F}(F)_{1} (\tau)\psi_{1}\bigl(\tau,u^{*}(\tau),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v^{*}(\tau)\bigr)\,d\tau\biggr)\,ds\\geq&t^{\beta-1}\max_{t\in\mathrm{J}}\int_{0}^{1}\mathcal{G}(1,s)\\&{}\ times\phi_{q}\biggl(\frac{1}{\varGamma(\sigma)}\int_{0}s}(s-\tau)^{\sigma-1}\mathcal{F}(F)_{1} (tau)\psi{1}\bigl(\tau,u^{*}(\tao),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v^{*}(\tau)\bigr)\,d\tau\biggr)\,ds\end{aligned}$$
暗示
$$u^{*}(t)\geq t^{\beta-1}\bigl\Vert u^{*.}\bigr\Vert\geq\frac{\hbar}{2}t^{\beta-1-}>0$$
类似地,我们得到
$$v^{*}(t)\geq t^{\beta-1}\bigl\Vert v^{*}\bigr\Vert\geq\frac{\hbar}{2}t^{\beta-1}>0$$
借助引理3.2和\((\mathcal){P}(P)_{3})\),解决方案\((u^{*},v^{*{)\)不会减少\(在数学中{J}). □
定理3.5
让假设
\((\mathbf{高}_{1})\)
到
\((\mathbf{高}_{3})\)
对…说实话
\(\Delta=\max\{\Delta_{1},\Delta_2}\}<1\),哪里
$$\开始{aligned}&\Delta_{1}=\frac{(q-1)\varrho^{q-1}(2\beta-\Delta)\mathcal{米}_{\psi_{1}}\垂直\mathcal{F}(F)_{1} \Vert}{(\beta-\delta)\varGamma(\beta+1)}\biggl[\frac{1}{\varGarma(\sigma+1)}+\frac}\mathcal{米}_{\psi_{2}}\垂直\mathcal{F}(F)_{2} \Vert}{\varGamma(\rho+1)}\biggr],\\&\Delta{2}=\frac{(q-1)\varrho^{q-1}(2\beta-\Delta)\mathcal{M'}{\psi{2}}\Vert\mathcal{F}(F)_{2} \Vert}{(\beta-\delta)\varGamma(\beta+1)}\biggl[\frac{\Vert\mathcal{F}(F)_{1} \Vert\mathcal{M'}_{\psi{1}}}{\varGamma(\sigma+1)}+\frac{1}{\valGamma[\rho+1)}\biggr]。\结束{对齐}$$
然后(1.1)有独特的解决方案。
证明
定义运算符\(\varPhi=(\varPhi_{1},\varPhi_{2}):\overline{\varOmega(r)}/\varOmega(r)\rightarrow{\mathbf{B}}\)通过
$$\varPhi(u,v)(t)=\bigl(\varPhi _{1}(u,v),\varPhi _{2}(u,v)\bigr)(t),\quad t\in\mathrm{J}$$
哪里
$$开始{对齐}[b]&\varPhi_{1}(u,v)(t)\\&\quad=\int_{0}^{1}\mathcal{G}^{\beta}(t,s)\phi_{q}\biggl(\frac{1}{\varGamma(\sigma)}\int_}^{s}(s-\tau)^{\sigma-1}\mathcal{F}(F)_{1} (τ)\psi{1}\bigl(τ,u(\tau),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\bigr)\,d\tau\biggr)\,ds\end{对齐}$$
和
$$开始{对齐}[b]&\varPhi_{2}(u,v)(t)\\&\quad=\int_{0}^{1}\mathcal{G}^{\beta}(t,s)\phi_{q}\biggl(\frac{1}{\varGamma(\sigma)}\int_}^{s}(s-\tau)^{\sigma-1}\mathcal{F}(F)_{1} (τ)\psi{1}\bigl(τ,u(\tau),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\bigr)\,d\tau\biggr)\,ds.\end{aligned}$$
现在,对于任何人\((u,v),(\bar{u},\bar{v},我们有
$$\开始{aligned}&\bigl\Vert\varPhi(u,v)-\varPhi(\frac{1}{\varGamma(\sigma)}\int_{0}^{s}(s-\tau)^{\sigma-1}\mathcal{F}(F)_{1} (τ)\psi{1}\bigl(τ,u(\tau),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}v(\tau)\biger)\bigr)\,d\tau\biggr)\,ds\\&\qquad{}-\phi_{q}\biggl(\frac{1}{\varGamma(\sigma)}\int_{0}^{s}(s-\tau)^{\sigma-1}\mathcal{F}(F)_{1} (tau)\psi{1}\bigl(\tau,\bar{u}(\tao),{}^{c} D类^{\rho}\bigl(\phi_{p} D类^{\beta}\bar{v}(\tau)\bigr)\,d\tau\biggr gl(\frac{1}{\varGamma(\rho)}\int_{0}^{s}(s-\tau)^{\rho-1}\mathcal{F}(F)_{2} (τ)\psi{2}\bigl(τ,{}^{c} D类^{\sigma}\bigl(\phi_{p} D类^{β}u(\tau)\bigr),v(\teau)\biger)\,d\tau\biggr)\,ds\\&\qquad{}-\phi_{q}\biggl(\frac{1}{\varGamma(\rho)}\int_{0}^{s}(s-\tau)^{\rho-1}\mathcal{F}(F)_{2} (τ)\psi{2}\bigl(τ,{}^{c} D类^{\sigma}\bigl(\phi_{p} D类^{\beta}\bar{u}(\tau)\bigr),\bar{v}(\tau)\biger)\,d\tau\biggr)\,ds\biggl|\biggr\}\\&\quad\leq\frac{(q-1)\varrho^{q-1}(2\beta-\delta)}{(\beta-\ delta)\varGamma(\beta+1)}\biggl[\frac}\mathcal{米}_{\psi_{1}}\垂直\mathcal{F}(F)_{1} \垂直\垂直u-\bar{u}\垂直+\mathcal{M}'{\psi_{1}}\mathcal{M}'{\psi.{2}}\Vert\mathcal{F}(F)_{1} \Vert\Vert\mathcal(垂直){F}(F)_{2} \Vert\Vert v-\bar{v}\Vert}{\varGamma(\sigma+1)}\\&\qquad{}+\frac{\mathcal{米}_{\psi_{1}}\mathcal{米}_{\psi_{2}}\Vert\mathcal{F}_{1}\Vert\mathcal{F}(F)_{2} 垂直u-\bar{u}\Vert+\mathcal{M}'{\psi_{2}}\|\mathcal{F}(F)_{2} 垂直v-\bar{v}\Vert}{\varGamma(\rho+1)}\biggr]\\&\quad\leq\frac{(q-1)\varrho^{q-1}(2\beta-\delta)\mathcal{米}_{\psi_{1}}\垂直\mathcal{F}(F)_{1} \Vert}{(\beta-\delta)\varGamma(\beta+1)}\biggl[\frac{1}{\varGarma(\sigma+1)}+\frac}\mathcal{米}_{\psi_{2}}\|\Vert\mathcal(垂直){F}(F)_{2} \Vert}{\varGamma(\rho+1)}\biggr]\Vert u-\bar{u}\Vert\\&\qquad{}+\frac{(q-1)\varrho^{q-1}(2\beta-\delta)\mathcal{M'}_{\psi_{2}}\Vert\mathcal{F}(F)_{2} \Vert}{(\beta-\delta)\varGamma(\beta+1)}\biggl[\frac{\Vert\mathcal{F}(F)_{1} \Vert\mathcal{M'}_{\psi_{1}}}{\varGamma(\sigma+1)}+\frac{1}{\valGamma)-(v,\bar{v})\bigr\Vert。\结束{对齐}$$
因此
$$\bigl\Vert\varPhi(u,v)-\varPhi$$
因此,假设\(增量<1)意味着操作员Φ是一种收缩。因此,根据定理2.9, (1.1)具有唯一的固定点。□